1) V(CH₄) = 0,376 L.T(CH₄) = 304 K.p(CH₄) = 1,5 atm 101325 Pa/atm = 151987,5 Pa = 151,9875 kPa.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(CH₄) = p · V ÷ R · T.n(CH₄) = 151,9875 kPa · 0,376 L ÷ 8,314 J/K· mol · 304 K.n(CH₄) = 0,0226 mol.V(CH₄) = n(CH₄) · Vm.V(CH₄) = 0,0226 mol · 22,4 dm³/mol.V(CH₄) = 0,506 dm³ = 0,506 L.
2) V(SO₂) = 5,2 L.p(SO₂) = 45,2 atm = 45,2 atm · 101,325 kPa/atm = 4579,89 kPa.T(SO₂) = 293 K.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(SO₂) = p · V ÷ R · T.n(SO₂) = 4579,89 kPa · 5,2 L ÷ 8,314 J/K· mol · 293 K.n(CH₄) = 9,77 mol.There is not enogh SO₂, 225 mol - 9,77 mol = 215,23 mol is needed.
3) p(He) = 3,50 atm · 101,325 kPa/atm = 354,63 kPa.V(He) = 4,00 L.n(He) = 0,410 mol.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.T = p · V ÷ R · n.T(He) = 354,63 kPa · 4,00 L ÷ 8,314 J/K· mol · 0,410 mol.T(He) = 416,14 K.n - amount of substance.
4) p(Ar) = 1,00 atm · 101,325 kPa/atm = 101,325 kPa.V(Ar) = 3,4 L.T(Ar) = 263 K.R = 8,314 J/K·mol.Use ideal gas law: p·V = n·R·T.n(Ar) = p · V ÷ R · T.n(Ar) = 101,325 kPa · 3,4 L ÷ 8,314 J/K· mol · 263 K.n(Ar) = 0,157 mol.n(Ar) = 0,157 mol + 2,5 mol = 2,657 mol.p(Ar) = 2,657 mol · 8,314 J/K· mol · 263 K ÷ 3,4 L.p(Ar) = 1708,74 kPa.

6 0

4 years ago

Tetrahydrofuran (THF) is a common organic solvent with a boiling point of 339 K. Calculate the total energy (q) required to conv

poizon [28]

Explanation:

For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.

$Q_{1} = mC_{1} \Delta T_{1}$

Putting the given values into the above equation as follows.

$Q_{1} = mC_{1} \Delta T_{1}$

= $27.3 g \times 1.70 J/g K \times 41$

= 1902.81 J

Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.

$Q_{2}$ = energy required = $mL_{v}$

$L_{v}$ = latent heat of vaporization

Therefor, calculate the value of energy required as follows.

$Q_{2}$ = $mL_{v}$

= $27.3 \times 444$

= 12121.2 J

Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.

$Q_{3} = mC_{2} \Delta T_{2}$

Value of $C_{2}$ = 1.06 J/g, $\Delta T_{2}$ = (373 -339) K = 34 K

Hence, putting the given values into the above formula as follows.

$Q_{3} = mC_{2} \Delta T_{2}$

= $27.3 g \times 1.06 J/g \times 34 K$

= 983.892 J

Therefore, net heat required will be calculated as follows.

Q = $Q_{1} + Q_{2} + Q_{3}$

= 1902.81 J + 12121.2 J + 983.892 J

= 15007.902 J

Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.

5 0

3 years ago

Where do glaciers come from

marusya05 [52]

Answer:GLACIERS ARE MADE UP OF FALLEN SNOW OVER MILLION YEARS, IN MOST OF POLAR REGIONS IT TURNS TO ICE AND WILL FLOW DOWNWARDS AND OUTWARDS UNDER ITS OWN PRESSURE

AND THE LARGEST GLACIER IN THE WORLD IS 60 MILES WIDE AND AROUND 270 MILES LONG.

IT COVERS 10% OF EARTH'S TOTAL LAND

Explanation:

4 0

4 years ago