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HACTEHA [7]
3 years ago
10

Hot asphalt poured onto flat ground cools to form a solid road surface. Chemical or physical change

Chemistry
1 answer:
Verdich [7]3 years ago
6 0
<h2>Answer:</h2>

This is a physical change.

<h3>Explanation:</h3>

Hot asphalt is mixed with the sand crushed stones and spread onto the roads, when it gets dry it becomes hard giving a smooth straight surface of the road.

Asphalt is used to stick together stones and sand in the road.

It is a physical change because the phase of the asphalt changed from the liquid to solid.

At high temperature, asphalt is in liquid form and at room temperature, it is present in hard solid form.

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Non-renewable energy is often called?​
DIA [1.3K]

Answer:

It is also called a finite resource

Explanation:

5 0
3 years ago
100 points plus i'll mark brainliest
sdas [7]
I think the answer is 98 grams
5 0
3 years ago
You are conducting a plant growth experiment and need to generate a solution with growth factor, auxin or indole-3-acetic acid.
Yuki888 [10]

Answer:

7,01 g of indole-3-acetic acid

Explanation:

The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of <em>0,4mol / L</em>

100mL are <em>0,1L</em>. Using these values:

0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.

As the MW of the molecule is 175,2 g/mol:

0,04mol × (175,2g / mol) = <em>7,01 g of indole-3-acetic acid</em>

<em></em>

Thus, <em>you need 7,01 g of indole-3-acetic acid to generate your solution</em>.

I hope it helps!

5 0
4 years ago
A 10.0 L flask at 318 K contains a mixture of Ar and CH4 with a total pressure of 1.040 atm. If the mole fraction of Ar is 0.715
andrey2020 [161]

Answer:

w_{Ar}=0.814

Explanation:

Hello,

In this case, given the temperature, volume and total pressure, we can compute the total moles by using the ideal gas equation:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.040atm*10.0L}{0.082\frac{atm*L}{mol*K}*318K}\\  \\n=0.41mol

Next, using the molar fraction of argon, we compute the moles of argon:

n_{Ar}=0.41mol*0.715=0.29mol

And the moles of methane:

n_{CH_4}=0.41mol-0.29mol=0.12mol

Now, by using the molar masses of both argon and methane, we can compute the mass percent of argon:

w_{Ar}=\frac{m_{Ar}}{m_{Ar}+m_{CH_4}}=\frac{0.29mol*\frac{40g}{1mol}  }{0.29mol*\frac{40g}{1mol}+0.12mol*\frac{16g}{1mol}}  \\\\w_{Ar}=0.814

Regards.

7 0
3 years ago
7. Wind, moving water, falling rocks, and roller-skating children are all examples of -​
cluponka [151]

Answer:

kinetic energy

the is because all of them are moving at once

5 0
3 years ago
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