After series of conversion from one unit to another, the number of gallons was found to be 12 litres
<h3>
Density, Mass and Volume</h3>
Given Data
- Density of Sulfuric acid = 1.84 g/cm3
- Mass of Sulfuric acid = 184.33 Pounds
Conversion from pounds to Gram
1 kg ---------2.204 lb
x kg ---------184.33 lb
x = 184.33/2.204
x = 83.634 kg
hence the mass in gram = 83.634*1000
mass in gram = 83634 g
Now let us find the volume
We know that density = mass/volume
volume = mass/density
volume = 83634/1.84
volume = 45453.26 cm^3
Convert cm^3 to litres
Volume in litres = 45453.26 /1000
Volume in litres = 45.45 Litres
Convert from Litres to Gallons
1 gallon = 3.79 L
x gallons = 45.45 L
x = 45.45/3.79
x gallons = 11.99 L
Approx = 12 Litres
Learn more about density here:
brainly.com/question/1354972
Answer:
Period and groups are different because
PERIODS are the number of shells
I.e in lame man words the no of circles when drawn an element
GROUPS : these are the number of electrons in the outermost shell
Groups determine the valency*
Answer:
The answer is: the number of unpaired valence electrons
Explanation:
The valence electrons are the number of electrons present in outer shell of an atom that participate in chemical bond formation, if the outer shell is not completely filled.
Covalent bond formation occurs when two atoms contribute one valence electron each to form a bond. Thus the number of covalent bonds that an element can form, can be determined by the number of unpaired valence electrons.
Therefore, the nature and the number of bonds formed by the element and the chemical properties of the element can be determined by the number of valence electrons present in the outer shell of the element.
Answer:
27.99 dm³
Explanation:
Applying
PV = nRT................ Equation 1
Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
From the question, we were aksed to find V.
Therefore we make V the subject of the equation
V = nRT/P................ Equation 2
Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
V = (1.31×310×0.082)/(1.1897)
V = 27.99 dm³
