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In-s [12.5K]
2 years ago
9

Calculate the force between two objects that have masses of 75. Kilograms and 2,100. Kilograms. Their centers of gravity are sep

arated by a distance of 1.00 meter.
Physics
2 answers:
iris [78.8K]2 years ago
4 0

Force = gravity x mass1 x mass2 / distance^2

Force = (6.67x10 ^-11) x (75) x (2100) / 1^2

Force = 1.050525 x 10 ^-5 Newtons

scoundrel [369]2 years ago
3 0

Answer:

use the formula above it's easy

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A 2.8-kg cart is rolling along a frictionless, horizontal track towards a 1.2-kg cart that is held initially at rest. The carts
agasfer [191]

Answer with Explanation:

We are given that

Mass of one cart,m_1=2.8 kg

Mass of second cart,m_2=1.2 kg

Initial velocity of one cart,u_1=4.6m/s

Initial velocity of second cart,u_2=-2.7 m/s

a.Total momentum,P=m_1u_1+m_2u_2=2.8(4.6)+1.2(-2.7)

P=9.64 kgm/s

b.Velocity of second cart,v_2=0

According to law of conservation of momentum

Initial momentum=Final momentum

9.64=2.8v_1+1.2\times 0

v_1=\frac{9.64}{2.8}

v_1=3.44m/s

8 0
4 years ago
A fishing boat uses a sonar device which sends sound waves to the water that travel at 1000 m/s. The fishing boat detects a sign
Alexeev081 [22]

I think its D answer

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6 0
3 years ago
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u
Hatshy [7]

Answer:

The  total energy is  T  =  169.02 \ J

Explanation:

From the question we are told that

    The  Poynting vector (energy flux ) is  k  =  0.939 \ W/m^2

    The length of the rectangle is  l  =  1.5  \ m

    The  width of the rectangle is  w =  2.0 \ m

    The time taken is t  =   1 \ minute  =  60 \ s

The total electromagnetic energy falls on the area is mathematically represented as

      T  =  k  *  A  *  t

Where A  is the area of the rectangle which is mathematically represented as

           A= l *  w

 substituting values

         A= 2 * 1.5

        A=  3 \ m^2

substituting values

        T  =  0.939 *  3 *  60

        T  =  169.02 \ J

5 0
4 years ago
A 240 N sphere 0.20 m in radius rolls, without slipping 6.0 m downa
Shalnov [3]

Answer:

The angular speed of the sphere at the bottom of the hill is 31.39 rad/s.

Explanation:

It is given that,

Weight of the sphere, W = 240 N

Radius of the sphere, r = 0.2 m

Angle with the horizontal, \theta=28^{\circ}

We need to find the angular speed of the sphere at the bottom of the hill if it starts  from rest.

As per the law of conservation of energy, the total energy at the top is equal to the energy at the bottom.

Gravitational energy = translational energy + rotational energy

So,

mgh=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

I is the moment of inertia of the sphere, I=\dfrac{2}{5}mr^2

Also, v=r\omega

h is the height of the ramp, h=l\ sin\theta

mgl\ sin\theta=\dfrac{1}{2}m(r\omega)^2+\dfrac{1}{2}I\omega^2

On solving the above equation we get :

\omega=\sqrt{\dfrac{10gl\ sin\theta}{7r^2}}

\omega=\sqrt{\dfrac{10\times 9.8\times 6\ sin(28)}{7(0.2)^2}}

\omega=31.39\ rad/s

So, the angular speed of the sphere at the bottom of the hill is 31.39 rad/s. Hence, this is the required solution.

6 0
3 years ago
If a car has a force of 900 N and has a mass of 650 kg. What would be the acceleration of the
777dan777 [17]
65 mph ;) your welcome
4 0
3 years ago
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