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3 years ago

An electric heater is rated 1000w, 250v. calculate the resistance

Physics

1 answer:

frez [133]3 years ago

4 0

Answer:

Correct answer: R = 62.5Ω

Explanation:

Power P = U · I = U · U/R = U²/R => P = U²/R => R= U²/P

R = 250²/1000 = 62.5Ω

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bazaltina [42]

Answer:

1. $t_2 = 2t_1$

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Explanation:

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$d = at^2$

So if the acceleration is halved while maintaining the same d:

$\frac{d_1}{d_2} = \frac{a_1t_1^2/2}{a_2t_2^2/2}$

As $d_1 = d_2$ , then $d_1/d_2 = 1$ . Also $a_1 = 2a_2$

$1 = \frac{2a_2t_1^2}{a_2t_2^2}$

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$t_2 = t_1\sqrt{2}\approx 1.14t_1$

So t increased by 1.14

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A quantum well is a region of semiconductor or metal film that confines particles to a small region, resulting in quantized ener

murzikaleks [220]

Answer:

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An electric heater is rated 1000w, 250v. calculate the resistance​

An electric heater is rated 1000w, 250v. calculate the resistance