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Harrizon [31]
3 years ago
12

A spherical shell of radius 1.4 m is placed in a uniform electric field with magnitude 5650 N/C. Find the total electric flux th

rough the shell. Answer in units of N · m 2 /C.\
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

The total electric flux through the shell = 34804 N.m²/C

Explanation:

φ = E.A ........................... Equation 1

Where φ = total electric flux through the shell, E = Electric Field, A =  surface Area of the sphere

But,

A = 4πr² ................................... Equation 2

Where r = radius of the sphere.

Given: r = 1.4 m,

constant: π = 3.143

Substituting these values into equation 2,

A = 3.143(1.4)²

A = 6.16 m²

Also Given: E = 5650 N/C,

Substituting into equation 1,

φ = 5650(6.16)

φ = 34804 N.m²/C

Thus the total electric flux through the shell = 34804 N.m²/C

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En la figura los émbolos son de masa despreciable y están en reposo, como se ve en la figura, siendo M=300 kg. Determine: a) la
Leni [432]

The image mentioned is in the attachment

Answer: a) P = 2450 Pa;

b) P = 2940 Pa;

c) F = 4.9 N

Explanation:

a) Pressure is a force applied to a surface of an object or fluid per unit area.

The image shows a block applying pressure on the large side of the piston. The force applied is due to gravitation, so:

P = \frac{F}{A}

P = \frac{m.g}{A}

P = \frac{300.9.8}{1.2}

P = 2450 Pa

The pressure generated by the block is P = 2450 Pa.

b) A static liquid can also exert pressure and can be calculated as:

P_{staticfluid} =ρ.g.h

where

ρ is the density of the fluid

h is the depth of the fluid

g is acceleration of gravity

P_{staticfluid} = 600.9.8.0.5

P_{staticfluid} = 2940 Pa

The pressure in the fluid at 50 cm deep is P_{staticfluid} = 2940 Pa.

c) For the system to be in equilibrium both pressures, pressure on the left side and pressure on the right side, have to be the same:

P_{s} = P_{b}

\frac{F}{A_s} = \frac{F_b}{A_b}

F = \frac{F_b}{A_b}.A_s

Adjusting the units, A_{s} = 0.002 m².

F = \frac{300.9.8.0.002}{1.2}

F = 4.9 N

The force necessary to be equilibrium is F = 4.9 N.

4 0
3 years ago
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