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Harrizon [31]
3 years ago
12

A spherical shell of radius 1.4 m is placed in a uniform electric field with magnitude 5650 N/C. Find the total electric flux th

rough the shell. Answer in units of N · m 2 /C.\
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

The total electric flux through the shell = 34804 N.m²/C

Explanation:

φ = E.A ........................... Equation 1

Where φ = total electric flux through the shell, E = Electric Field, A =  surface Area of the sphere

But,

A = 4πr² ................................... Equation 2

Where r = radius of the sphere.

Given: r = 1.4 m,

constant: π = 3.143

Substituting these values into equation 2,

A = 3.143(1.4)²

A = 6.16 m²

Also Given: E = 5650 N/C,

Substituting into equation 1,

φ = 5650(6.16)

φ = 34804 N.m²/C

Thus the total electric flux through the shell = 34804 N.m²/C

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uniform electric field of magnitude 365 N/C pointing in the positive x-direction acts on an electron, which is initially at rest
vfiekz [6]

Answer:

a)   W = - 1.752 10⁻¹⁸ J,  b)    U = + 1.752 10⁻¹⁸ J

Explanation:

a) work is defined by

         W = F . x

the bold letters indicate vectors, in this case the force is electric

         F = q E

we substitute

         F = q E x

the charge of the electron is

         q = - e

         F = - e E x

let's calculate

         W = - 1.6 10⁻¹⁹  365  3 10⁻²

         W = - 1.752 10⁻¹⁸ J

b) the change in potential energy is

          U = q ΔV

the potential difference is

          ΔV = - E. Δs

 

we substitute

         U = - q E Δs

the charge of the electron is

           q = - e

          U = e E Δs

we calculate

           U = 1.6 10⁻¹⁹ 365  3 10⁻²

           U = + 1.752 10⁻¹⁸ J

3 0
3 years ago
What movements of water has the greatest effect on the growth of producers
kolbaska11 [484]
The movement of water that has the greatest effect on the growth of producers is <em><u>upwelling</u></em><em><u /></em>.

Upwelling is a rising of a liquid. The reason upwelling is much better for producers is because it is a slow rising in the water level, preventing erosion to the topsoil and still giving the necessary amount of water and nutrients the producers need.

Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if you need any more help with anything :D <span />
5 0
3 years ago
Use your calculator to evaluate -3.7 meter/second-13.9 meter/second 21.4 second-72 second
cluponka [151]

Answer :

(-3.7 meter/second) - (13.9 meter/second) = -17.6 meter/second

(21.4 second) - (72 second) = -50.6 second

Explanation :

(1) As we are given the expression :

(-3.7 meter/second) - (13.9 meter/second)

Now we have to evaluate this expression, we get:

⇒ -17.6 meter/second

(2) As we are given the expression :

(21.4 second) - (72 second)

Now we have to evaluate this expression, we get:

⇒ -50.6 second

6 0
3 years ago
A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

5 0
3 years ago
A 15.0 kg turntable with a radius of 25 cm is covered with a uniform layer of dry ice that has a mass of 9.0 kg. The angular spe
liubo4ka [24]

Answer:

 ω₂=1.20

Explanation:

Given that

mass of the turn table ,M= 15 kg

mass of the ice ,m= 9 kg

radius ,r= 25 cm

Initial angular speed ,ω₁ = 0.75 rad/s

Initial mass moment of inertia

I_1=\dfrac{M+m}{2}r^2

I_1=\dfrac{15+9}{2}\times 0.25^2\ kg.m^2

I_1=0.75\ kg.m^2

Final mass moment of inertia

I_2=\dfrac{M}{2}r^2

I_2=\dfrac{15}{2}\times 0.25^2\ kg.m^2

I_2=0.468\ kg.m^2

Lets take final speed of the turn table after ice evaporated =ω₂ rad/s

Now by conservation angular momentum

I₁ ω₁ =ω₂ I₂

\omega_2=\dfrac{0.75\times 0.75}{0.468}\ rad/s

ω₂=1.20

7 0
3 years ago
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