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Harrizon [31]
3 years ago
12

A spherical shell of radius 1.4 m is placed in a uniform electric field with magnitude 5650 N/C. Find the total electric flux th

rough the shell. Answer in units of N · m 2 /C.\
Physics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

The total electric flux through the shell = 34804 N.m²/C

Explanation:

φ = E.A ........................... Equation 1

Where φ = total electric flux through the shell, E = Electric Field, A =  surface Area of the sphere

But,

A = 4πr² ................................... Equation 2

Where r = radius of the sphere.

Given: r = 1.4 m,

constant: π = 3.143

Substituting these values into equation 2,

A = 3.143(1.4)²

A = 6.16 m²

Also Given: E = 5650 N/C,

Substituting into equation 1,

φ = 5650(6.16)

φ = 34804 N.m²/C

Thus the total electric flux through the shell = 34804 N.m²/C

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Answer and Explanation:

(a) The fre-body diagrams for each block is shown below. In the block of mass 3.60 kg, there are 3 forces acting on it: horizontal force due to the rope (F_{t}), vertical gravitational force (F_{g}) and vertical normal force (F_{n}), due to the surface. Since there is no vertical movement, F_{g} and F_{n} cancels it out. So, for this block, net force is horizontal due to the rope F_{t}.

The block of mass m is hanging from the pulley, so there is the force of the rope (F_{t}) and the gravitational force (F_{g}). Both are vertical, because there is no surface "holding" block m.

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a=\frac{F_{r}}{m}

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a = 5.22

The acceleration of either block is 5.22 m/s².

(c) Block m has 2 forces acting on it: tension and gravitational force. Gravitational force is the force of attraction the Earth does over an object. It is calculated as the product of mass and gravitational acceleration, which has magnitude g = 9.8 m/s².

Suppose positive referential is going up. To determine mass:

F_{r}=m.a

F_{t}-F_{g}=m.a

F_{t}-m.g=m.a

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Block m has 1.25 kg.

(d) Gravitational force is also called weight. So, as described above: F_{g}=m.g.

The weight for the hanging block is

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Answer:

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Taking the relative initial velocity of the man and the woman as 0 m/s, we have;

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The final velocity of the man, her partner = v₂₁ ≈ -1.04 m/s.

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