Answer:
a) W = - 1.752 10⁻¹⁸ J, b) U = + 1.752 10⁻¹⁸ J
Explanation:
a) work is defined by
W = F . x
the bold letters indicate vectors, in this case the force is electric
F = q E
we substitute
F = q E x
the charge of the electron is
q = - e
F = - e E x
let's calculate
W = - 1.6 10⁻¹⁹ 365 3 10⁻²
W = - 1.752 10⁻¹⁸ J
b) the change in potential energy is
U = q ΔV
the potential difference is
ΔV = - E. Δs
we substitute
U = - q E Δs
the charge of the electron is
q = - e
U = e E Δs
we calculate
U = 1.6 10⁻¹⁹ 365 3 10⁻²
U = + 1.752 10⁻¹⁸ J
The movement of water that has the greatest effect on the growth of producers is <em><u>upwelling</u></em><em><u /></em>.
Upwelling is a rising of a liquid. The reason upwelling is much better for producers is because it is a slow rising in the water level, preventing erosion to the topsoil and still giving the necessary amount of water and nutrients the producers need.
Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if you need any more help with anything :D <span />
Answer :
(-3.7 meter/second) - (13.9 meter/second) = -17.6 meter/second
(21.4 second) - (72 second) = -50.6 second
Explanation :
(1) As we are given the expression :
(-3.7 meter/second) - (13.9 meter/second)
Now we have to evaluate this expression, we get:
⇒ -17.6 meter/second
(2) As we are given the expression :
(21.4 second) - (72 second)
Now we have to evaluate this expression, we get:
⇒ -50.6 second
Answer:
27,000 m
450 m/s
Explanation:
Assuming the initial velocity is 0 m/s:
v₀ = 0 m/s
a = 15 m/s²
t = 60 s
A) Find: Δy
Δy = v₀ t + ½ at²
Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²
Δy = 27,000 m
B) Find: v_avg
v_avg = Δy / t
v_avg = 27,000 m / 60 s
v_avg = 450 m/s
Answer:
ω₂=1.20
Explanation:
Given that
mass of the turn table ,M= 15 kg
mass of the ice ,m= 9 kg
radius ,r= 25 cm
Initial angular speed ,ω₁ = 0.75 rad/s
Initial mass moment of inertia



Final mass moment of inertia



Lets take final speed of the turn table after ice evaporated =ω₂ rad/s
Now by conservation angular momentum
I₁ ω₁ =ω₂ I₂

ω₂=1.20