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Ksenya-84 [330]
3 years ago
9

Please help me out !!!!!!

Physics
1 answer:
nikdorinn [45]3 years ago
8 0

Answer:

89

Explanation:

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The​ time, t, required to drive a fixed distance varies inversely as the​ speed, r. It takes 3 hr at a speed of 14 ​km/h to driv
kenny6666 [7]

Answer:

time taken with speed 23 km/h will be 1.8 hours or 1 hour 48 minutes

Explanation:

Given:

Time is inversely proportional to the speed

mathematically,

t ∝ (1/r)

let the proportionality constant be 'k'

thus,

t = k/r

therefore, for case 1

time = 3 hr

speed = 14 km/hr

3 = k/14

also,

for case 2

let the time be = t

r = 23 km/h

thus,

we have

t = k/23

on dividing equation 2 by 1

we get

\frac{t}{3}=\frac{k/23}{k/14}

or

t=\frac{14\times3}{23}

or

t = 1.8 hr = or 1 hour 48 minutes ( 0.8 hours × 60 minutes/hour = 48 minutes)

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2 years ago
When approaching an intersection, bridge, or railroad crossing, you should never drive (pass on the left half of the roadway whe
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You should not go into the left side of the roadway when within 100 feet of the crossing. Moreover, you should also turn on your turn signal when within 100 of a turn. These precautions prevent accidents as it makes clear to other drivers what your intentions are and drivers making turns are not endangered. 
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3 years ago
Hooke's Law Practice
Oxana [17]

Answer:sheeExplanation:

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2 years ago
A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the
Genrish500 [490]

Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

a_c =w^2r = \frac{v^2}{r}

in this case we know the speed of the runner

v =8.00\ m/s

The radius "r" will be the distance from the runner to the center of the track

r = 28.2\ m

a_c = \frac{8^2}{28.2}\ m/s^2

a_c = 2.27\ m/s^2

The answer is the last option

3 0
3 years ago
Write the realtionship between the density of a liquid and its upthrust? clarify​
kipiarov [429]

Answer:

B = ρ g V_liquid

the thrust is proportional to the density of the liquid

Explanation:

The density of a liquid is defined as the relationship between the mass and the volume of the liquid

         ρ = m / V

The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid

        B = W_liquid

        B = m _liquid g

we substitute mass for density

        B = ρ g V_liquid

therefore we see that the thrust is proportional to the density of the liquid

8 0
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