Answer:
The quantity of motion is the measure of the same, arise from the velocity and quantity of matter conjointly. In other words, rather than defining the quantity of motion of a given object as simply the kinematic velocity v of the object, he defined it as the product mv, where m is the mass of the object.
Explanation:
<span>Chronological essays by the definition of a chronological
meaning in order. There is an order in a specific writing. Like a history write
up from a certain happening years ago. It
is different from procedural essays because these are essays who are giving
instructions of certain set up to guide the person accordingly in doing
something to make it more accurate. Like recipes, instructions in playing, etc.
Example words that are used in chronological essays are first, second, third,
fourth, fifth, next, after, then, lastly, finally, consequently, in addition,
thus, therefore, however, etc.</span>
Answer:
1. the force which can be felt or act only when two objects are in contact is known as contact force.
for example: frictional force, muscular force,
tension, air resistance .
2. the force which can be felt or act even when two objects are in contact or not is known as non-contact force.
for example: magnetic force, gravitational force, electrostatic force.
Answer:3764.282 KPa
Explanation:
Given gusher shoots oil at h=25 m
i.e. the velocity of jet is
v=\sqrt{2gh}[/tex]
v=22.147 m/s
Now the pressure loss in pipe is given by hagen poiseuille equation
For 25 m head in terms of Pressure
Total Pressure=
=3543.557+220.725=3764.282 KPa
a₀). You know ...
-- the object is dropped from 5 meters
above the pavement;
-- it falls for 0.83 second.
a₁). Without being told, you assume ...
-- there is no air anyplace where the marshmallow travels,
so it free-falls, with no air resistance;
-- the event is happening on Earth,
where the acceleration of gravity is 9.81 m/s² .
b). You need to find how much LESS than 5 meters
the marshmallow falls in 0.83 second.
c). You can use whatever equations you like.
I'm going to use the equation for the distance an object falls in
' T ' seconds, in a place where the acceleration of gravity is ' G '.
d). To see how this all goes together for the solution, keep reading:
The distance that an object falls in ' T ' seconds
when it's dropped from rest is
(1/2 G) x (T²) .
On Earth, ' G ' is roughly 9.81 m/s², so in 0.83 seconds,
such an object would fall
(9.81 / 2) x (0.83)² = 3.38 meters .
It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was
(5.00 - 3.38) = 1.62 meters
above the pavement. That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.
