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3 years ago

The ksp of iron(ii) hydroxide, fe(oh)2, is 4.87 × 10-17. calculate the molar solubility of this compound.

1 answer:

7 0

When iron hydroxide dissolves, it dissociates as follows
Fe(OH)₂ --> Fe²⁺ + 2OH⁻
molar solubility is the number of moles of solute that can be dissolved is a 1 L solution
if molar solubility of Fe(OH)₂ is x then molar solubility of Fe²⁺ is x and OH⁻ is 2x
the solubility product constant - ksp formula is ;
ksp = [Fe²⁺][OH⁻]²
ksp = (x)(2x)²
ksp = x * 4x²
ksp = 4x³
ksp = 4.87 x 10⁻¹⁷
4x³ = 4.87 x 10⁻¹⁷
x = 2.30 x 10⁻⁶ M
molar solubility of Fe(OH)₂ is 2.30 x 10⁻⁶ M

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3 years ago

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How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh

Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0

3 years ago

A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200

Sedbober [7]

Answer:

81°C.

Explanation:

To solve this problem, we can use the relation:

where, Q is the amount of heat released from water (Q = - 1200 J).

m is the mass of the water (m = 20.0 g).

c is the specific heat capacity of water (c of water = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).

∵ Q = m.c.ΔT

∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).

(- 1200 J) = 83.72 final T - 7953.

∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.

<em>So, the right choice is: 81°C.</em>

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3 years ago

Consider the structures of vinegar and triglyceride and draw in any bond dipoles that exist in the molecules above using a dipol

bagirrra123 [75]

Answer:

Given molecules are vinegar and triglycerides.

Explanation:

The dipole is a vector quantity and it is heading from less electronegative atom to more electronegative atom in a polar covalent bond.

The structures and the bond dipoles in the given molecules are shown below:

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3 years ago

Select the answer which shows the correct order, slowest to fastest, of the relative rate of diffusion of the gases.

IrinaK [193]

Diffusion is the process of a substance spreading out to evenly fill its container or environment. Rate of diffusion of a gas is inversely proportional to the molar mass of the gas.

$Rate of diffusion \propto \frac{1}{Molar mass}$

Lighter(lower) the molar mass of the gas , faster will be its rate of diffusion and heavier (higher) the molar mass of the gas , slower will be its rate of diffusion.

We have to arrange the given gases from slowest rate of diffusion to fastest rate of diffusion that means we need to arrange gases from higher molar mass to lower molar mass.

Molar mass of given gases are :

Cl = 35.5 g/mol

Xe = 131.29 g/mol

He = 4.00 g/mol

N = 14.00 g/mol

So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :

Xe , Cl , N , He

Xe having the highest molar mass will have the slowest rate of diffusion and He with lowest molar mass will have the fastest rate of diffusion, so option 'c' is correct.

Note : Slowest rate of diffusion = High Molar Mass

Fastest rate of diffusion = Low Molar Mass

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3 years ago