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3 years ago

Movement of electrons about a central nucleus is a concept by whom?

Chemistry

2 answers:

Burka [1]3 years ago

7 0

Answer:

Bohr.

Explanation:

In 1913, N.Bohr proposed an atomic model for atom. He proposed that in an atom there is a central nucleus and electrons move around this center in a fixed path known as shell.

The shells or path have a fixed size and energy. The electrons do not lose energy during this movement.

There is possibility of energy change (emit or absorb) in an electron if they move from one shell to another.

Alenkasestr [34]3 years ago

5 0

The answer is bohr hope this helps :)

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A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200

Anarel [89]

Answer:

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Explanation:

Side of the cubic box = s = 20.0 cm

Volume of the box ,V= $s^3$

$V=(20.0 cm)^3=8000 cm^3=8\times 10^{-3} m^3$

Root mean square speed of the of helium molecule : 200m/s

The formula used for root mean square speed is:

$\mu=\sqrt{\frac{3kN_AT}{M}}$

where,

= root mean square speed

k = Boltzmann’s constant = $1.38\times 10^{-23}J/K$

T = temperature = 370 K

M = mass helium = $3.40\times 10^{-27}kg/mole$

$N_A$ = Avogadro’s number = $6.022\times 10^{23}mol^{-1}$

$T=\frac{\mu _{rms}^2\times M}{3kN_A}$

Moles of helium gas = n

Number of helium molecules = N = $2.00\times 10^{23}$

N = $N_A\times n$

Ideal gas equation:

PV = nRT

Substitution of values of T and n from above :

$PV=\frac{N}{N_A}\times R\times \frac{\mu _{rms}^2\times M}{3kN_A}$

$PV=\frac{N\times R\times \mu ^2\times M}{3k\times (N_A)^2}$

$R=k\times N_A$

$PV=\frac{N\times \mu ^2\times M}{3}$

$P=\frac{2.00\times 10^{23}\times (200 m/s)^2\times 3.40\times 10^{-27} kg/mol}{3\times 8\times 10^{-3} m^3}$

$P=1133.33 Pa =1.133 kPa$

(1 Pa = 0.001 kPa)

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

3 0

3 years ago

A plastic ball with a volume of 19.7cm^3 has a mass of 15.8g Would this ball sink or float in a container of gasoline?

katrin [286]

Answer:

It would sink because the density of the ball, 0.802 g/cm3, is greater than the density of gasoline.

6 0

3 years ago

Calculate the number of oxygen atoms in 1.58g of kmnO4

zvonat [6]

Answer: i think it's 4 oxygen atoms

Explanation:

so sorry if i'm wrong

3 0

3 years ago

Kate’s blood volume is 3.8L. Before treatment,if her blood glucose was 170 mg/dL, how many grams of glucose were in her blood?

LiRa [457]

Answer:

6.460 gm is the correct answer .

Explanation:

Given

Kate’s blood volume= $3.8L$

blood glucose= $170\ mg/dL$

As we know that

$1\ dL= 10^{-1}\ litre$

The $10^{-1}$ includes the blood glucose of the $170\ mg/dL,$

So $3.8L.$ of the Kate’s blood volume can be determined by

$=\ \frac{170 * 3.8 }{10^{-1} }$

$=170 * 38 \ mg$

$=6460\ mg$

To convert into the gm we have divided by the 1000

$6.460 \ gm$

Therefore the glucose in her blood=

$6.460 \ gm$

3 0

3 years ago

Read 2 more answers

PLEASE HELP ASAPPPP

Liono4ka [1.6K]

So what you do is you write out each element separately and how many of that element on either side of the arrow S-8|S-1
O-2|O-2
on one side theres 8 (S) and 2 (O) and 1(S) and 2(O) if you put a number in front to balance it you are multiplying it the elements number like
SO2 if I put a 2 in front now I will have 2(S) and 4(O)

Answer is 1,8,8

8 0

4 years ago