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Kitty [74]
4 years ago
11

Think about what you know about science today. How do you think scientific knowledge will be different in 100 years?

Chemistry
1 answer:
algol [13]4 years ago
3 0

Answer:

I think we will know a lot more about the universe and the things around us. We may also know a lot more about other planets, such as Mars and Saturn, and we might also know a lot more about other stars in the universe.

Explanation:

You might be interested in
While out on a hike, you find an unknown mineral. How would you test the mineral to find out what it is?
Mashcka [7]
Probably look up the descriptions of the element and see if it matches the mineral.
5 0
3 years ago
I need help! What arrange these elements in order of increasing density: gallium, germanium arsenic
solong [7]

Answer:

germanium -5.5g/cm^3

arsenic -5.73g/cm^3

gallium -5.91g/cm^3

Explanation:

I hope I helped

3 0
2 years ago
Which reaction illustrates the conservation of matter during a redox reaction
Jet001 [13]
<span>This question is simple, answers are D and C respectively</span>
6 0
3 years ago
What sort of nucleophile does NADH supply?
Elden [556K]

Answer:

Hydride ion

Explanation:

You often see the reduction with NADH written as

NADH ⟶ NAD⁺ + H⁺ + 2e⁻

If you think about it, H⁺ + 2e⁻ is equivalent to H:⁻, so we could write the reaction as

NADH ⟶ NAD⁺ + H:⁻

In terms of a mechanism, the dihydropyridine ring of NADH transfers a hydrogen atom with its pair of electrons (a hydride ion) to the substrate and becomes the more stable, aromatic pyridinium ion in NAD⁺.

7 0
4 years ago
011 10.0 points
Sphinxa [80]

Answer:

-58.3^{\circ}C

Explanation:

The frequency and the wavelength of a wave are related by the equation

v=f\lambda

where

v is the speed

f is the frequency

\lambda is the wavelength

For the sound wave in this problem, we have

f = 634 Hz (frequency)

\lambda=0.47 m (wavelength)

Therefore, the speed of the wave is

v=(634)(0.47)=298 m/s

The speed of sound in air depends on the temperature according to the equation

v=333+0.6 T

where T is the temperature.

In this problem, we know the speed, so we can calculate the temperature:

T=\frac{v-333}{0.6}=\frac{298-333}{0.6}=-58.3^{\circ}C

7 0
3 years ago
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