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3 years ago

Which liquids are highly sensitive to both changes in temperature and changes in the electrical field?

Chemistry

2 answers:

lilavasa [31]3 years ago

5 0

Answer:

Liquid crystals

Explanation:

Mumz [18]3 years ago

3 0

Liquid crystal molecules have very unique structures, allowing them to be highly affected by electric fields, changing their orientation in the liquid crystal structure. This is why they are used in LCD screens. They are also highly sensitive to changes in temperature. Therefore the answer is C.
Hope this helps!

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If you combine 230.0 mL 230.0 mL of water at 25.00 ∘ C 25.00 ∘C and 120.0 mL 120.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t

Thepotemich [5.8K]

Answer: The final temperature of the mixture is 49°C

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

For cold water:

Density of cold water = 1 g/mL

Volume of cold water = 230.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{230.0mL}\\\\\text{Mass of water}=(1g/mL\times 230.0mL)=230g$

For hot water:

Density of hot water = 1 g/mL

Volume of hot water = 120.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g$

When hot water is mixed with cold water, the amount of heat released by hot water will be equal to the amount of heat absorbed by cold water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of hot water = 120 g

$m_2$ = mass of cold water = 230 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of hot water = 95°C

$T_2$ = initial temperature of cold water = 25°C

c = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]$

$T_{final}=49^oC$

Hence, the final temperature of the mixture is 49°C

4 0

4 years ago

How is burning magnesium different from burning methane?

trasher [3.6K]

Answer:

oxygen and magnesium come together in a chemical to form a reaction to it compound after it burns then it forms white powder of magnesium oxide but in the process magnesium gives up 2 electrons to oxygen atoms to form powdery product.

when you burn methane it crrates a blue flame in sufficient amounts of oxygen methane burns to give off carbon dioxide (Co2) and water (H2o)

8 0

3 years ago

CaCO3(s) + HCl(aq) -> CO2(g) + H2O(l) + CaCl2(aq)

andrew11 [14]

Explanation:

$CaCO _{3(s)} + 2HCl _{(aq)}→ CO _{2(g)} + H2O _{(l)} + CaCl _{2(s)}$

3 0

3 years ago

Polar solvents dissolve____solutes and nonpolar solvents____solutes.

Ber [7]

Generally speaking only certain molecules will dissolve in water to begin with. The old phrase "like dissolves like" or "birds of a feather flock together" is very true with respect to what degree solutes are soluble or miscible in different solvents. At very low concentrations, almost all molecules are somewhat soluble in all solvents. But by trend, ionic and polar solutes are more soluble in polar solvents and non-polar molecules are soluble in non-polar (mostly organic) solvents. The units of concentration we just discussed are used to describe the degree to which a solute is soluble in a solvent.

When you place a non-polar molecule in a polar solvent (like oil in water) the molecules try to minimize surface contact between them. (like you and a guy with a cold on an elevator). This is actually the basis for the cells in our bodies. The lipids (oily fatty acids) form our cell membranes so that their non-polar tails face inward away from the polar cytoplasm and the polar heads face towards the polar cytoplasm.

7 0

4 years ago

Read 2 more answers

When heated, KClO3 decomposes into KCl and O2. If this reaction produced 88.4 g of KCl, how much O2 was produced (in grams)? 2KC

adoni [48]

Mass of KCl= 88.4g
Molar mass of KCl=39+35.5
 =74.5
 The Moles of KCl= 88.4/74.5
 =1.186
If for the 2 moles of KCl there are 3 moles of oxygen
so

1 mole of KCl will give=3/2=1.5 moles of oxygen

1.186 moles of KCl will give =1.5*1.186=1.779 oxygen
32 the molar mass of oxygen
so its mass will be
1.779 *32=56.928
enjoy

5 0

3 years ago