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lana [24]
3 years ago
10

Which of the following can lower the activation energy of a system?

Physics
1 answer:
exis [7]3 years ago
8 0
Catalysts
a catalyst is something added to a reaction that speeds it up (or lowers the activation energy)

increasing the temp would speed up the whole reaction but not lower the activation energy
so B.
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A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of
Alchen [17]

Answer:

The speed of the block when it is 5.00 m from the top of the incline is 3.04 m/s

Explanation:

given information:

s = 7.80 m

v = 3.8 m/s

if s = 5 m, v?

first we have to find the acceleration of the block using the following equation:

v² = v₀² + 2as, v₀²  = 0 thus

3.8² = 2 a 7.8

a = 0.93

so, if s = 5m the final speed is

v² = 2 (0.93) (5)

   = 9.26

v = √9.26

  = 3.04 m/s

5 0
4 years ago
IF YOUR GOOD AT SCIENCE THEN PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST
Digiron [165]

Answer:

This is an open circuit

Explanation:

An open circuit I believe

It needs to be closed for the bulb to be turned on

8 0
3 years ago
Why do we have thunder storms
Over [174]
Thunderstorms happen when cold air sinks and hot air rises in rapid succession. There has to be an unstable body of hot air for a thunderstorm to happen. Cool air mingles with the hot air causing condensation (that means that raindrops form) This makes a cumulous cloud.
The moisture in the cloud is either positively charged or negatively charged. Negatively charged particles sink to the bottom of the cumulous cloud while positively charges particles rise. The positive and negative charges rub together and spark causing lightning.
Thunder is formed by the lightning, a bolt of lightning is hollow, and has no air inside it. When the lightning dissipates the air rushes to fill the space breaking the sound barrier in the process, this creates the boom. 

3 0
3 years ago
If a current of 2. 4 a is flowing in a wire of diameter 2. 0 mm, what is the average current density?
HACTEHA [7]

The average current density is 7.6 × 10⁵ A/m².

To calculate the current density current will be 2.4 A.

Diameter of a wire = 2mm.

The cross-sectional area of the wire is given by r = d/2

where r is the radius of the wire.  

Then, the cross-sectional area is = 0.00000314159265

                                                                   = 3.1 × 10⁻⁶ m².

<h3>What is average current density?</h3>

         Consider a current carrying conductor, the current density depends upon  the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.

Average current density j = I / A Ampere/ meter².

By substituting the values in the formula,

             j = 2.4 / ( 3.1 × 10⁻⁶)

               = 7.6 × 10⁵ A/m².

Hence, the current density can be calculated.

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5 0
2 years ago
Drag the positive or negative feedback loop on the left to each process on the right. terms may be used once, more than once, or
slamgirl [31]

The order of the positive and negative feedback loops are positive, positive, negative, positive, positive, negative.

<h3>What is a feedback loop?</h3>

A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent actions. A minimum of four phases comprise each feedback loop. Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.

Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for sustaining an ideal condition. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.

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5 0
2 years ago
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