Answer:
$84
Explanation:
The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.
The heater consumed by the heater is 1200 kWh.
For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:
Electric input to heat pump = 1200 / 2.4 = 500 kWh
That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh
The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh
Money saved = $0.12/kWh * 700 kWh = $84
(vx)f=(vx)i + a(t)
since it starts from rest the initial velocity is zero so you can do some algebra and get your (a).
Answer
given,
mass of raindrop = 5.4 × 10⁻⁷ kg
acceleration due to gravity = 9.8 m/s²
a) magnitude of gravitational force on the rain drop
Force on the rain drop = m g
Force on the rain drop = 5.4 × 10⁻⁷ x 9.8
= 5.292 x 10⁻⁶ N
Hence, force on raindrop by earth is equal to 5.292 x 10⁻⁶ N
b) by newtons third law
Force by the earth on the raindrop will be opposite to the force by raindrop on earth.
Force on earth by raindrop = - 5.292 x 10⁻⁶ N
negative sign represent that force is acting in the opposite direction.
Answer:
17.97m/s
Explanation:
Density of air (ρ)air=1.23 kg/m3, and
Air speed (V) =20 m/sec, pressure gradient along the streamline, ∂p/∂x = 100N/m^3.
The equation of motion along the stream line directions:
considering the momentum balance along the streamline.
γsinθ-∂p/∂x=ρV(∂V/∂x)
Neglecting the effect of gravity , then γ=ρg=0
So, ∂p/∂x= -ρV(∂V/∂x)
∂V/∂x= - 100/(20X1.23)= -4.0650407/S
Also δV/δx=∂V/∂x
∂V/∂x=-4.0650407/S and δx=0.5 m
δV = (-4.0650407/S) *(0.5m)
δV = -2.0325203 m/S
So net air speed will be V+δV= -2.0325203+20 ≅17.96748 m/s
Approximately, V+δV=17.97m/s.
