For Part A.
The absolute value of vector A is
<span>|A | = 6
This is simply the square root of the sum of the squares of the coordinates.
For Part B
Do the same thing as in Part A
| B | = </span>√14
<span>
Part C
Simply subtract the corresponding elements resulting in
(-3, 2, 7)
Part D
</span>√62
<span>
Part E
Yes</span>
Answer:
scalar quantity
Explanation:
Vector quantities have two characteristics, a magnitude and a direction. Scalar quantities have only a magnitude.
Answer:
E = 1/2 M V^2 + 1/2 I ω^2 = 1/2 M V^2 + 1/2 I V^2 / R^2
E = 1/2 M V^2 (1 + I / (M R^2))
For a cylinder I = M R^2
For a sphere I = 2/3 M R^2
E(cylinder) = 1 + 1 = 2 omitting the 1/2 M V^2
E(sphere) = 1 + 2/3 = 1.67
E(cylinder) / E(sphere) = 2 / 1.67 = 1.2
The cylinder initially has 1.20 the energy of the sphere
The PE attained is proportional to the initial KE
H(sphere) = 2.87 / 1/2 = 2.40 m since it has less initial KE
