Joint committees have similar purposes as select committees, but they are made up of members from both the House and the Senate. They are set up to conduct business between the houses and to help focus public attention on major issues.
C. a lot of inertia.............................. :-)
yup they r equal as mentioned above is equal magnitude and direction! so they r totally equal.
as one vector has 2 things which is used to define it ->
- Magnitude
- direction
so if both r equal then both vectors r equal vectors
To solve this problem, apply the concepts given from Ohm's Law. From there we will obtain the derivative of the function with respect to time and with the previously given values we will proceed to find the change in current as a function of the derivative

Here
I = Current
V = Voltage
R = Resistance
Taking the derivative we will have,

Our values are given as,




Replacing we will have that


Rearranging to find the current through the time,


Therefore the change of the current is -0.000026A per second