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Pepsi [2]
2 years ago
10

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

228 loops, is 3.13 V. The emf induced in coil 2 is 4.16 V. How many loops does coil 2 have
Physics
1 answer:
Nat2105 [25]2 years ago
5 0

Answer:

303

Explanation:

We are given that

Emf in coil 1,E_1=3.13 V

Emf induced in coil 2,E_2=4.16 V

Number of loops in coil 1,N_1=228

We have to find the number of loops in coil 2.

Rat of change of magnetic flux in a single loop is same.

Let \phi_1 and \phi_2 be the magnetic flux in coil 1 and coil 2.

\frac{d\phi_1}{dt}=\frac{d\phi_2}{dt}

\frac{V_2}{V_1}=\frac{N_2}{N_1}

Using the formula

\frac{E_2}{E_1}=\frac{N_2}{N_1}

\frac{4.16}{3.13}=\frac{N_2}{228}

N_2=\frac{4.16}{3.13}\times 228

N_2=303

Hence, the number of loops in coil 2=303

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