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Pepsi [2]
3 years ago
10

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

228 loops, is 3.13 V. The emf induced in coil 2 is 4.16 V. How many loops does coil 2 have
Physics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

303

Explanation:

We are given that

Emf in coil 1,E_1=3.13 V

Emf induced in coil 2,E_2=4.16 V

Number of loops in coil 1,N_1=228

We have to find the number of loops in coil 2.

Rat of change of magnetic flux in a single loop is same.

Let \phi_1 and \phi_2 be the magnetic flux in coil 1 and coil 2.

\frac{d\phi_1}{dt}=\frac{d\phi_2}{dt}

\frac{V_2}{V_1}=\frac{N_2}{N_1}

Using the formula

\frac{E_2}{E_1}=\frac{N_2}{N_1}

\frac{4.16}{3.13}=\frac{N_2}{228}

N_2=\frac{4.16}{3.13}\times 228

N_2=303

Hence, the number of loops in coil 2=303

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What's the surface temperature of a woodstove with surface area 1.4 m2 that radiates energy at the rate of 18 kw? treat the stov
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Answer:

Assuming the emissivity is 1.0, the temperature of the wood stove will be about 417 C

Explanation:

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Assuming the emissivity ( a number between 0 and 1) is 1.0, the temperature of the wood stove will be about 417 C. The emissivity number was not given in your question. If you determine what it is, you can divide this result by the fourth power of that value to get an updated result.

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