Question

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has 228 loops, is 3.13 V. The emf induced in coil 2 is 4.16 V. How many loops does coil 2 have

Answer 1

Answer:

303

Explanation:

We are given that

Emf in coil 1,$E_1=3.13 V$

Emf induced in coil 2,$E_2=4.16 V$

Number of loops in coil 1,$N_1=228$

We have to find the number of loops in coil 2.

Rat of change of magnetic flux in a single loop is same.

Let $\phi_1$ and $\phi_2$ be the magnetic flux in coil 1 and coil 2.

$\frac{d\phi_1}{dt}=\frac{d\phi_2}{dt}$

$\frac{V_2}{V_1}=\frac{N_2}{N_1}$

Using the formula

$\frac{E_2}{E_1}=\frac{N_2}{N_1}$

$\frac{4.16}{3.13}=\frac{N_2}{228}$

$N_2=\frac{4.16}{3.13}\times 228$

$N_2=303$

Hence, the number of loops in coil 2=303