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forsale [732]
3 years ago
15

Which part of modern atomic theory was first developed by John Dalton?

Chemistry
2 answers:
kirill [66]3 years ago
8 0

Answer:

C. Atoms are arranged during chemical reactions

Explanation:

All matter is made of atoms and atoms are indivisible and indestructible. compounds are formed by a combination of two or more different kinds of atoms.

tigry1 [53]3 years ago
4 0
A. ATOMS CAN NOT BE DIVIDED (INDIVISIBLE)
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Alja [10]
It’s deceleration hope that helps!
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3 years ago
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If 4.0 g of helium gas occupies a volume of 22.4 L at 0 o C and a pressure of 1.0 atm, what volume does 3.0 g of He occupy under
WINSTONCH [101]

Answer:

the volume occupied by 3.0 g of the gas is 16.8 L.

Explanation:

Given;

initial reacting mass of the helium gas, m₁ = 4.0 g

volume occupied by the helium gas, V = 22.4 L

pressure of the gas, P = 1 .0 atm

temperature of the gas, T = 0⁰C = 273 K

atomic mass of helium gas, M = 4.0 g/mol

initial number of moles of the gas is calculated as follows;

n_1 = \frac{m_1}{M} \\\\n_1 = \frac{4}{4} = 1

The number of moles of the gas when the reacting mass is 3.0 g;

m₂ = 3.0 g

n_2 = \frac{m_2}{M} \\\\n_2 = \frac{3}{4} \\\\n_2 = 0.75 \ mol

The volume of the gas at 0.75 mol is determined using ideal gas law;

PV = nRT

PV = nRT\\\\\frac{V}{n} = \frac{RT}{P} \\\\since, \ \frac{RT}{P} \ is \ constant,\  then;\\\frac{V_1}{n_1} = \frac{V_2}{n_2} \\\\V_2 = \frac{V_1n_2}{n_1} \\\\V_2 = \frac{22.4 \times 0.75}{1} \\\\V_2 = 16.8 \ L

Therefore, the volume occupied by 3.0 g of the gas is 16.8 L.

4 0
3 years ago
Whose model of the atom did J.J. Thomson prove to be incorrect with his Cathode-Ray tube experiments?
Brut [27]
JJ Thomson proved John Dalton's theory wrong, as Thomson discovered the electron. This showed that there were particles that were smaller than an atom, despite Dalton claiming that the atom is the smallest unit of matter.
7 0
3 years ago
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A temperature change in a reaction indicates_____.
natita [175]

A temperature change in a reaction indicates a chemical change

8 0
3 years ago
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A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As
TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

P.V=n.R.T=\frac{m}{M} .R.T

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g

7 0
3 years ago
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