Answer:
Lyrics C :like an open circuit at high frequencies and a short circuit at low frequencies
Explanation:
The impedance produce by the presence of an inductance in an electric circuit has a general equation Z(r) = jωl where j is the imaginay number, l is the inductor in henrios and ω is the frecuency of the curent ( ω = 2πf , f is the frecuency in hertz)
So module of the inductance directly depends on ω = 2πf then when f the frecuency increase, the value of ωl, also increase and when the value of f decrease ωl will decrease. For very high value of ω the inductance can become very very high ( even up to an open circuit ) and the opposite for very low values of frecuencies ωl could be very low (as to a short circuit
Answer:
The peak output voltage of this generator is 314.2 V.
Explanation:
Given;
the number of turns of the coil, N = 1000 turns
area of the coil, A = 0.001 m²
angular frequency of the coil, f = 100 cycles/seconds
magnitude of the magnetic field, B = 0.5 T
The peak output voltage of this generator is given by;
E = NBAω
Where;
ω is the angular velocity = 2πf
E = NBA(2πf)
E = 1000 x 0.5 x 0.001(2 x π x 100)
E = 314.2 V
Therefore, the peak output voltage of this generator is 314.2 V.
Answer:
α = 5 rad / s²
Explanation:
This is a rotational kinematics exercise.
They indicate the initial velocity wo = 10 rad / s
w = w₀ + α t
α =
let's calculate
α =
α = 5 rad / s²
The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change
a = α r
v = w r
Answer:
Explanation:
From the exercise we know that the force on the plane is 7934N upward at an angle of 54.2º.
If analyze the forces in the vertical direction, the acceleration is zero because the plane is moving with constant velocity
∑
So, the <u><em>weight of the plane</em></u> is 6435N