Answer:
Explanation:
Let's use Ohm's law:
or
(1)
Where:
We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:
(2)
Where:
Keep in mind that the electrical resistivity of the gold is a known constant which is 
and the cross sectional area of the conductor is calculated as:
Because we have a wire in this case, so we assume a cylindrical geometry.
Now replacing our data in (2)
Finally, we know R and V, so replacing these values in (1) we will be able to find the current:
from the question
x₁ = x-coordinate = 8
y₁ = y-coordinate = - 4
m = slope of line = 2/3
slope form of the line is given as
(y - y₁ ) = m (x - x₁)
inserting the values
(y - (- 4) ) = (2/3) (x - 8)
(3) (y + 4) = (2) (x - 8)
multiplying each term inside the bracket by 3 and 2 respective on left and right side
3y + 12 = 2 x - 16
2 x - 3 y - 16 - 12 = 0
2 x - 3 y - 28 = 0
185 newtons because (W=Fd so W/d=F)296/1.6=185
Self productive and it depends on how whom is behaving.
Answer:
686.11 N
1.7733 gallons
Explanation:
= Efficiency = 30%
V = Volume of gasoline
E = Energy content of gasoline = 
F = Force
s = Displacement = 108000 m
v = Velocity
Work done is given by
The force required to keep the car moving at a constant speed is 686.11 N
Here the force is directly proportional to speed
The gallons that will be used is 1.7733 gallons
