Question

g A wheel of radius 1.2 meters initially rotates clockwise around its center with an angular speed of 10 rad/s, and it steadily increases its rate of rotation. 4 second later, the rate of rotation is 30 rad/s. What is the ratio of the angular acceleration of a point on the rim of the wheel to a point that is 0.6 meters from the center of the wheel?

Answer 1

Answer:

 α = 5 rad / s²

Explanation:

This is a rotational kinematics exercise.

They indicate the initial velocity wo = 10 rad / s

             w = w₀ + α t

             α = $\frac{w-w_o }{t}$

let's calculate

             α = $\frac{30-10}{4}$

             α = 5 rad / s²

The velocity, the angular relation are the same in all the points of the wheel, the velocities and linear accelerations are the ones that change

            a = α r

            v = w r