Answer:
b
c
e
h
Explanation:
Note that the swing direction was not giving in the question and direction could be sideways (in a turn) or in a track or both
The question show something in common ...acceleration
So let's look at the statements and pick the correct ones
a is false while b is correct as the train is accelerating
c is correct. The train is accelerating even thou the speed could not be ascertained
d is false and not feasible as the train is accelerating
e is true as the train maybe moving at a constant speed in a circle
f is false. This could be constant velocity in a circle. Same as g (false)
h is true. It's accelerating
<h3><u>Answer;</u></h3>
1st drop; Motor
2nd drop; Electricity
A device that uses electricity and magnetism to create motion is called a <u>motor</u>. In a reverse process, a device that uses motion and magnesium can be used to create <u>electricity</u>.
<h3><u>Explanation</u>;</h3>
- <em><u>Motors are device which use electricity and magnetism to create motion.</u></em> They pass alternating current through opposing pairs of magnets to create a rotating magnetic field which creates a magnetic field in the rotor of a motor, making it to spin around.
- <em><u>Electric motors work in a reverse process by using motion and magnetism to generate electricity. </u></em>When a coil or loops of wire are exposed to a changing magnetic field, an electrical current arises or is induced.
As per impulse momentum theorem we know that
![F\Delta t = m(v_f - v_i)](https://tex.z-dn.net/?f=F%5CDelta%20t%20%3D%20m%28v_f%20-%20v_i%29)
now here we will have
![F = 6.50 \times 10^3 N](https://tex.z-dn.net/?f=F%20%3D%206.50%20%5Ctimes%2010%5E3%20N)
t = 1.30 ms
m = 0.144 kg
![v_i = -43 m/s](https://tex.z-dn.net/?f=v_i%20%3D%20-43%20m%2Fs)
now we need to find final speed using above formula
![(6.50 \times 10^3)(1.30 \times 10^{-3}) = 0.144 ( v_f - (-43))](https://tex.z-dn.net/?f=%286.50%20%5Ctimes%2010%5E3%29%281.30%20%5Ctimes%2010%5E%7B-3%7D%29%20%3D%200.144%20%28%20v_f%20-%20%28-43%29%29)
![v_f = 15.7 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2015.7%20m%2Fs)
so final speed is given as above
Here,
height at failure, h1 = 525 m,
upward acceleration, a = 2.25 m/s^2,
velocity = v m/s,
<span>
SO, </span>
<span>
v^2 = 2*a*h = 2*2.25*525 = 2362.5 </span>
Now, acceleration, g = 9.8 m/s^2,
<span>
SO, </span>
<span>
heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters </span>
Hence,
<span>
a) </span>
Total height = 525+120.54 = 645.54 meters
b)
<span>time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec
---------------------------------
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Answer: magnitude of the instantaneous angular velocity
Explanation:
Instantaneous angular speed is refered to as the magnitude of the instantaneous angular velocity. We should note that the instantaneous angular velocity is the rate that has to do with the rotation of an object in circular path.