Answer:
Explanation:
Mass = 624 gm = .624 kg
weight = .624 x 9.8
= 6.11 N
Radius of ball = 12.15 x 10⁻² cm
volume of ball
= 4/3 x 3.14 x ( 12.15 x 10⁻²)³
= 7509.26 x 10⁻⁶ m³
Buoyant force = weight of displaced water
= 7509.26 x 10⁻⁶ x 10³ x 9.8
= 73.59 N
b ) Since buoyant force exceeds the weight of the ball , it will float .
c )
Let volume v sticks out while floating .
Volume under water
= 7509.26 x 10⁻⁶ - v
its weight
= (7509.26 x 10⁻⁶ - v ) x 10³ x 9.8
For floating
(7509.26 x 10⁻⁶ - v ) x 10³ x 9.8 = .624 x 9.8 ( weight of ball )
(7509.26 x 10⁻⁶ - v ) x 10³ = .624
7.509 - v x 10³ = .624
v x 10³ = 7.509 - .624
v x 10³ = 6.885
v = 6.885 x 10⁻³ m³
fraction
= v / total volume
= 6.885 x 10⁻³ / 7.51 x 10⁻³
91.67 %
Answer:
1: the refracted angle in the first face is equal to the incident angle that is 60degrees
2. Emergence Angle is 42degrees
Explanation:
Pls see attached file
W = F x d/x = (m x Ag) x h, therefore, mass (2kg x 9.8) x 2.5m = 49J
