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ipn [44]
4 years ago
10

Question 5 (2 points)

Physics
1 answer:
Radda [10]4 years ago
5 0

Answer:

Increase the work being done or decrease the time in which the work is completed

Explanation:

I got it right on the quiz i just took :)

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Explain what is happening in this<br> induction example.
Semmy [17]

Answer:

An electrical field duh

Explanation:

None needed self explanitory

4 0
2 years ago
Plssss help I need good grade!!!! Plssss and thank u
shepuryov [24]

Answer:

the answer is 'b'

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8 0
3 years ago
Read 2 more answers
A force F acting on an object of mass m causes a displacement d. The angle between these two vectors is Θ. The work W done on th
777dan777 [17]
Work:
W= \int\limits^b_a {F.} \, ds

F: force
ds: displacement

Assuming the work is constant:

W= \int\limits^b_a {F.} \, ds =  F . d = F * cos\theta * d

d displacement


4 0
3 years ago
On his fishing trip Justin takes the boat 25 km south. The fish aren’t biting so he goes 10 km west. He follows a school of fish
S_A_V [24]

Distance is 50 km

Displacement is 10 km

<u>Explanation:</u>

Given:

Distance toward south, x = 25 km

Distance towards west, y = 10 km

Distance towards north, z = 15 km

(a) Total distance, D = ?

Total distance, D = x + y + z

                       D = 25 + 10 + 15

                       D = 50km

(b) Displacement, d = ?

Displacement = final position - initial position

                      = 10 - 0 km

                      = 10km

8 0
3 years ago
A student sits on a freely rotating stool holding two weights, each of mass 3.10 kg. When his arms are extended horizontally, th
fgiga [73]

Answer

Give that,

mass of two student m = 3.10 kg  

distance from the axis of the rotation is r = 1 m

angular speed ω = 0.754 rad /s  

moment of inertia I = 3.10 kg m²

position from the rotation of the axis is r_1 = 0.29 m

Total moment of inertia I '   = I + 2 m r²

                                          = 3.1 +2 x 3.1 x( 1)^2  

                                           = 9.3 kg m²

moment of inertia inward horizontally from the position of rotation axis is  

                                   I"   = I + 2 m r^2  

                                         = 3.1 + 2 * 3.1 kg ( 0.29)^2  

                                         = 3.62 kg m^2  

a ) new angular speed is ω_1 =\dfrac{I'\omega}{I''}

                                               = \dfrac{9.3\times 0.754}{3.62}  

                                               = 1.94 rad /s

b ) K.E before the system pulls weight inward is

K.E = \dfrac{1}{2} I' \omega^2

K.E = \dfrac{1}{2}\times 9.3 \times 0.754^2

K.E =2.64\ J

c )K.E after the system pulls weight inward is

K.E = \dfrac{1}{2} I'' \omega_1^2

K.E = \dfrac{1}{2}\times 3.62 \times 1.92^2

K.E =6.67\ J

3 0
3 years ago
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