Answer:
Q = 768.47 J
Explanation:
Given that,
Mass of the metal, m = 25 g
Initial temperature, T₁ = 21.0 ºC
Final temperature, T₂ = 80.0 ºC
The specific heat of the metal is 0.521 J/gºC.
We know that the heat released due to the change in temperature is given by :
Hence, 768.47 J of heat energy will be needed.
Answer:
3.5 mol KClO3
Explanation:
Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.
x mole of KClO3 = 3.5 mol KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3
x mole of KClO3 = 3.5 mol KClO3
Answer:
two atoms both non metals
Explanation:
because if the bond is formed between atoms with similar electronegativity since covalent bonding is the sharing of electrons
Answer:
474.3 cm³
Explanation:
Given data:
Initial volume of chlorine gas = 568 cm³
Initial temperature = 25°C
Final volume = ?
Final temperature = -25°C
Solution:
Initial temperature = 25°C (25+273 = 297 K)
Final temperature = -25°C (-25 +273 = 248 K)
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 568 cm³ × 248 K /297 K
V₂ = 140864 cm³.K / 297 K
V₂ = 474.3 cm³
Dipole-dipole interactions, and London dispersion interactions
