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pochemuha
3 years ago
6

You performed the experiment using air which we know is actually a mixture of several gases. would the results of this experimen

t be improved
Chemistry
1 answer:
yulyashka [42]3 years ago
8 0
Air is a mixture of gases like nitrogen, oxygen and traces of other gases like argon and many others. To improve this experiment, the mixture should be separated into its components to avoid contamination. In order to achieve this, you can use the cryogenic process, which is a distillation process at very low temperatures. In this case, you can use pure nitrogen or pure oxygen for your experiment.
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g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o
Liono4ka [1.6K]

Answer:

<u><em></em></u>

  • <u><em>pOH = 0.36</em></u>

Explanation:

Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.

<u>1. Potassium hydroxide solution, KOH</u>

  • Volume, V = 304 mL = 0.304 liter
  • Molarity, M = 0.36 M
  • number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol
  • 1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

<u>2. LIthium hydroxide, LiOH</u>

  • Volume, V = 341 mL = 0.341 liter
  • Molarity, M = 0.51 M
  • number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol
  • 1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

<u />

<u>3. Resulting solution</u>

  • Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

  • Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

  • Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

<u />

<u>4. </u><em><u>pOH</u></em>

      pOH=-\log [OH^-]=-\log (0.439)=0.36   ← answer

5 0
3 years ago
What best explains the type of energy present in the wheels of a moving bus
OverLord2011 [107]
Kinetic energy due to the movement
8 0
4 years ago
Read 2 more answers
A 1.513 g sample of KHP (C8H5O4K) is dissolved in 50.0 mL of DI water. When the KHP solution was titrated with NaOH, 14.8 mL was
son4ous [18]

Answer:

0.501 M

Explanation:

  • KHP + NaOH → NaKP + H₂O

First we <u>convert 1.513 g of KHP into moles</u>, using its <em>molar mass</em>:

  • 1.513 g ÷ 204.22 g/mol = 7.41x10⁻³ mol = 7.41 mmol

As <em>1 mol of KHP reacts with 1 mol of NaOH</em>, in 14.8 mL of the NaOH solution there were 7.41 mmoles of NaOH.

With the above information in mind we can <u>calculate the molarity of the NaOH solution</u>:

  • 7.41 mmol / 14.8 mL = 0.501 M
3 0
3 years ago
A 7.27-gram sample of a compound is dissolved in 250 grams of benzene. The freezing point of this solution is 1.02°C below that
almond37 [142]

Answer:

146 g/mol → option b.

Explanation:

This is a problem about the freezing point depression. The formula for this colligative property is:

ΔT = Kf . m . i

We assume i = 1, so our compound is not electrolytic.

ΔT = Freezing T° of pure solvent - Freezing T° of solution = 1.02 °C

m  = molality (mol of solute/kg of solvent)

We convert the grams of solvent (benzene) to kg → 250 g . 1 kg/1000 = 0.250 kg.

We replace → 1.02°C = 5.12°C/mol/kg . mol/ 0.250kg . 1

1.02°C / 5.12 mol/kg/°C = mol/ 0.250kg

0.19922 mol/kg = mol/ 0.250kg

mol = 0.19922 . 0.250kg → 0.0498 mol

molar mass = g/mol → 7.27 g / 0.0498mol = 146 g/mol

5 0
3 years ago
if the reactant solution is used to write on a piece of paper and the paper is allowed to partially dry, what can be done to bri
marissa [1.9K]

Answer:

Expose the paper to the atmosphere or moisture

Explanation:

An interesting experiment that demonstrates the equilibrium of complexes is that of the invisible ink.

The invisible ink is pink colored [Co(H2O)6]Cl2 which is essentially colorless and pale when it is used to write on paper. This complex is almost colorless when dilute. Therefore, when it is used in writing, the writing can not be seen.

However, if the paper is left to stand or allowed to absorb moisture; the following equilibrium is set up:

[Co(H2O)6]Cl2 ⇄ [CoCl2(H2O)2] + 4H2O

The formation of blue [CoCl2(H2O)2] on standing or exposure to moisture enables the colored writing to be easily read.

3 0
3 years ago
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