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Sauron [17]
3 years ago
12

Help quick? Which of the following statements best compares nuclear power and hydropower based on their rates of renewal?

Chemistry
1 answer:
liubo4ka [24]3 years ago
5 0

Answer:

Hydropower has a faster rate because water is continuously being recycled through the hydrogeological cycle.

Explanation:

The source of hydropower is mostly from water which is a part of the hydrogeological cycle. Water is renewed at a faster rate within the weather system from time to time. We can easily forecast and predict an areas potency of generating hydro-electricity. Water is a renewable resources.

For nuclear power, the source is geological. Not all elements are radioactive. A certain condition must be fulfilled for spontaneous radioactivity in an isotope. Minerals are mined for their useful radioactive materials which serves as fuels in nuclear power plant. Geological processes takes a very long time to occur and so the sources of nuclear power is not easily renewed. In fact, they are classified as part of non-renewable resources.  

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Consider the reaction between iodine gas and chlorine gas to form iodine monochloride. A reaction mixture at 298.15k initially c
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Step 1 : Write balanced chemical equation

The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

I_{2}  (g) + Cl_{2}  (g) ----->  2 ICl (g)

Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

- The initial concentration of product is assumed as 0

- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products

- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

K_{eq} = \frac{[ICl]^{2}}{[I_{2}][Cl_{2}]}

Step 4 : Solving for x

Keq at 298.15 K is given as 81.9

Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table

81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]

4x^{2} = 81.9x^{2} -57.8x +9.66

77.9x^{2} -57.8x+9.66 = 0

Solving the above equation using quadratic formula we get

x = 0.488 or x = 0.254

The value 0.488 cannot be used because the change (C) cannot be greater that initial concentration of the reactants.

Therefore the change in concentration of the gases during the reaction is 0.254 M

Hence, x = 0.254 M

From the ICE table, we know that the equilibrium concentration of ICl is 2x

[ICl]_{eq} = 2 ( 0.254) = 0.508 M

The concentration of ICl when the reaction reaches equilibrium is 0.508 M

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