Answer:
There are many equations for oxidation and reduction, but the most relevant ones are the equations for the half-reactions. In general, the equation for oxidation is:
Oxidation: Reducing Agent + O2 → Oxidizing Agent
And the equation for reduction is:
Reduction: Oxidizing Agent + e- → Reducing Agent
These equations show the transfer of electrons that occurs during oxidation and reduction.
Explanation:
Answer:-3463 kJ and -3452kJ
Explanation:
ΔU is the change in internal energy of a system and its formula is;
ΔU = q + w
Where q represents heat transferred into or out of the system. Its value is positive when heat is transfer into the system and negative when heat is produced by the system.
W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.
For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.
Therefore,
ΔU = -q-w
ΔU = -3452 kJ – 11kJ
= - 3463kJ
ΔH is the change in the enthalpy of a system and its formuls is;
ΔH = ΔU + Δ(PV)
By product rule Δ(PV) becomes ΔPV + PΔV
At constant pressure ΔP = 0. Therefore,
ΔH = -q-w + PΔV
w is equals to PΔV, So:
ΔH = -q
ΔH = -3452kJ
The collision must have sufficient energy as well. If sufficient energy is not present the activation energy will not be over come and the bonds in the reactants will not be broken.
I hope this helps. Let me know if anything is unclear.
Answer:
6.67 mg/kg per dose ( 26.67 mg/kg per day)
Explanation:
400 mg / 60 kg = 6 2/3 mg/kg per dose
per <em>DAY</em> is four times this number
