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densk [106]
3 years ago
6

A spring with a spring constant of 45 N/m is pulled 1.4 m away from its equilibrium position. How much potential energy is store

d in the spring?
Physics
1 answer:
Luda [366]3 years ago
7 0

Elastic potential energy is given by:

E =\dfrac{1}{2}kx^2

Where k is the spring constant in N/m and x is displacement from equilibrium position in m. Evaluating:

E =\dfrac{1}{2}kx^2 = \dfrac{1}{2}(45\;N/m)(1.4\;m)^2 = 44.1\;J

A/ The potential energy is stored in the spring is 44.1 J.

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