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Archy [21]
3 years ago
13

Define the reflection with diagram​

Physics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray. If a perpendicular were to be drawn on reflecting surface, it would be called normal. The figure below shows the reflection of an incident beam on a plane mirror.

Explanation:

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Physical properties of minerals graphic organizer
Nadusha1986 [10]
The answer is in the attachment
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4 0
3 years ago
A wheel of diameter 40.0 cm starts from rest and rotates with a constant angular acceleration of 3.00 rad/s^2. At the instant th
xxMikexx [17]

Answer:

ac= 15.07 m/s²

Explanation:

The Wheel rotates with a constant angular acceleration.:

Centripetal acceleration is calculated as follows:

ac =ω² *R   Formula (1)

ac =v² / R    Formula (2)

Kinematics of the wheel

We apply the equations of circular motion uniformly accelerated :

ωf²= ω₀² + 2αθ  Formula (3)

v = ω* R Formula (4)

Where:

θ : angle that the wheel has rotated in a given time interval (rad)

α : angular acceleration (rad/s²)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed   ( rad/s)

v: tangential velocity of a point on the rim ( m/s)

R : radius of  wheel (m)

ac: centripetal acceleration, (m/s²)

Data:

D = 40.0 cm : diameter of the wheel

R = D/2= 40.0 cm/ 2 = 20 cm = 0.2m

α = 3.00 rad/s^2

ω₀ = 0

n = 2 revolutions : number of revolutions

θ =2πn (rad) = 2π*2 (rad) = 4π rad

Calculate of the ωf

We replace data in the formula (3)

ωf²= ω₀² + 2αθ

ωf²= 0 + 2(3)(4π)

ωf²= 24π

w_{f} = \sqrt{24\pi }

ωf = 8.68 rad/s

Calculate of the v

We replace data in the formula (4)

v = ω*R

v = (8.68)*(0.2)

v = 1.736 m/s

Calculate of the ac

We replace data in the formula (1)

ac = ( ω)²*(R)

ac = (8.68)²*(0.2)

ac = 15.07  m/s²

We replace data in the formula (2)

ac = v²/ R

ac = ( 1.736  )²/(0.2)

ac = 15.07  m/s²

7 0
4 years ago
A particle with charge q and momentum p, initially moving along the x-axis, enters a region where a uniform magnetic field* B=(B
VMariaS [17]

Answer:

Magnitude of momentum = q × B0 × [d^2 + 2L^2] / 2d.

Explanation:

So, from the question, we are given that the charge = q, the momentum = p.

=> From the question We are also given that, "initially, there is movement along the x-axis which then enters a region where a uniform magnetic field* B = (B0)(k) which then extends over a width x = L, the distance = d in the +y direction as it traverses the field."

Momentum,P = mass × Velocity, v -----(1).

We know that for a free particle the magnetic field is equal to the centrepetal force. Thus, we have the magnetic field = mass,.m × (velocity,v)^2 / radius, r.

Radius,r = P × v / B0 -----------------------------(2).

Centrepetal force = q × B0 × v. ----------(3).

(If X = L and distance = d)Therefore, the radius after solving binomially, radius = (d^2 + 2 L^2) / 2d.

Equating Equation (2) and (3) gives;

P = B0 × q × r.

Hence, the Magnitude of momentum = q × B0 × [d^2 + 2L^2] / 2d.

4 0
3 years ago
When is the kinetic energy of an electron transformed into potential energy?
8090 [49]

Answer:

when it interacts with other electrons without changing its speed

Explanation:

without changing its speed

4 0
3 years ago
The outside diameter of your teacher's rear bicycle tire is 16 inches. How far will he travel if the rear wheel makes 1200 revol
FinnZ [79.3K]

Answer:

241,274.32 inches

Explanation:

How far will he travel if the rear wheel makes 1200 revolutions on the road?

Since the rear wheel makes one revolution in the distance of a circumference of a circle, C with diameter, d = 16 inches

C = πd²/4

So, the distance, travelled in 1200 revolutions is D = 1200 × C = 1200πd²/4

Substituting d = 16 into D, we have

D = 1200πd²/4

D = 1200π(16)²/4

D = 76800π

D = 241,274.32 inches

3 0
3 years ago
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