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kotegsom [21]
3 years ago
7

Can air be forced into a smaller space? Explain with an example.

Physics
1 answer:
enot [183]3 years ago
3 0

Answer:

Yes. Yes, you can.

Explanation:

Combinations of increased pressure and decreased temperature force gases into containers that we use every day. You might have compressed air in a spray bottle or feel the carbon dioxide rush out of a can of soda. Those are both examples of gas forced into a smaller space at a greater pressure.

Hope this helps :)

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Which unit would be most appropriate for measuring the mass of a black bean?
madam [21]

Answer:

milligrams

explanation:

kilograms are too big

<em>Hope this helps :)</em>

5 0
4 years ago
Which of the following careers would physicists be least qualified to perform,
Semmy [17]
D

Source? Trust Me Bro
4 0
3 years ago
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The rate of distance traveled per unit of time, without regard to direction
masya89 [10]

Answer: Speed

Explanation:

The speed of a body is the rate of distance (in metres) that it travels in one second. Hence, speed unlike velocity, is total distance travelled by the body without regard to direction divided by the total time taken.

i.e Speed = Distance / time taken

Thus, the standard international (SI) unit of speed is metres per second (m/s)

6 0
4 years ago
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A 120N box is being pushed across the surface that has a frictional force of 3N. If the box is being pushed with a constant forc
VashaNatasha [74]

Answer:

Net Force = 10 N

acceleration: a=0.817 \frac{m}{s^2}

Explanation:

1) The net force on the box is the applied force (F = 13 N) minus the friction force (f = 3 N), Therefore, net force = 10 N

See attached free body diagram.

2) To find the box's acceleration, we need first to find the mass of the box (since they are giving us its weight in Newtons). To do such we use the equation for weight and solve for the box's mass:

weight=m*g\\120 N = m*9.8\frac{m}{s^2} \\\frac{120}{9.8} kg = m\\m=12.24 kg

Now we can find the box's acceleration by using the equation for the net force:

F=m*a\\10N = 12.24 kg * a\\\frac{10}{12.24} \frac{m}{s^2} =a\\a=0.817 \frac{m}{s^2}

5 0
3 years ago
Estimate the average power output of the sun, given that about 1350 w/m2 reaches the upper atmosphere of the earth.
fenix001 [56]

the <u>average powe</u><u>r</u> output of the sun is <u>3.8 × </u>10^{26}<u> W</u> given that about 1350 w/m2 reaches the upper atmosphere of the earth.

As we know intensity falling over a surface is equal to Energy falling per unit area per unit volume.

I = \frac{Energy}{area*time}

Since Power is equal to energy/time

I = power/area

or

Power = Intensity × area

Now, Distance from Sun to Earth , r = 149.6 ×10^{9}  m

So, Surface area of the sphere of radius is:

A = 4 π r^{2}

= 4 × 3.14 × (149.6 × 10^{9})²

=  2.81 × 10^{23}m²

Thus Average Power output of the sun will be:

P = 1350 × 2.81 × 10^{23}

= 3.7935 × 10^{26}

P = 3.8 ×    10^{26}  W

So the average power output of the sun is 3.8 × 10^{26} W.

If you need to learn more about about the average power of a resistor, click here.

brainly.com/question/12972958

#SPJ4

7 0
2 years ago
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