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Aleonysh [2.5K]

3 years ago

7

in an experiment performed in a space station a force of 6 n causes an object to have an acceleration equal to 4 m / S2 II what

is the object's Mass

1 answer:

spayn [35]3 years ago

8 0

F = m A

m = F / A

m = 6N / 4m/s^2

m = 1.5 kg

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20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volu

boyakko [2]

It is given that that initial volume of gas is 20 cubic inches.

The initial pressure is given as 5 psi.

The final pressure is given as 10 psi

We are asked to calculate the final volume.

Let initial and final volume of gas is denoted as $v_{1} \ and\ v_{2}$

Let the initial and final pressure of gas is denoted as $p_{1} \ and\ p_{2}$

As per the question the temperature of a gas is constant.

From Boyle's law we know that pressure of a given mass of a gas is inversely proportional to the applied volume at constant temperature.

Hence mathematically

$p\ \alpha\ \frac{1}{v}$

$pv=constant$

$p_{1} v_{1} =p_{2} v_{2}$

$v_{2} =\frac{p_{1}v_{1} }{p_{2} }$

Putting the values of these respective quantities as mentioned above we get-

$v_{2} =\frac{5\ psi*20 cubic\ inches}{10\ psi}$

$=10\ cubic\ inches$ [ans]

8 0

3 years ago

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What is the condition to earths atmosphere at a givin time and pace

alina1380 [7]

The condition of earths atmosphere at a given time and place is the weather.

6 0

3 years ago

How are electrical current measured

katrin2010 [14]

Answer:

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6 0

3 years ago

The diameter of an automobile tire is closest to

slamgirl [31]

Answer:

(1) 10^−2 m

Explanation:

The diameter of the tire of an automobile is generally expressed in centimetres; we can say that the diameter of a tire is generally about

d = 20 cm (20 centimetres)

Now we have to verify which option is closest to this value. To do that, we have to keep in mind the equivalence between metres and centimetres; in fact, we have:

$1 cm = 10^{-2} m$

This means that we can rewrite the diameter of the tire of a car as

$d=20 cm = 20\cdot 10^{-2} m$

By comparing it with the given options, we see that the closest option is

(1) 10^−2 m

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6 0

4 years ago

A photon detector captures a photon with an energy of 4.29 ✕ 10−19 J. What is the wavelength, in nanometers, of the photon?

serious [3.7K]

Answer : The wavelength of photon is, $4.63\times 10^{2}nm$

Explanation : Given,

Energy of photon = $4.29\times 10^{-19}J$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength of photon = ?

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$4.29\times 10^{-19}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}$

$\lambda=4.63\times 10^{-7}m=4.63\times 10^{-7}\times 10^9nm=4.63\times 10^{2}nm$

Conversion used : $1nm=10^{-9}m$

Therefore, the wavelength of photon is, $4.63\times 10^{2}nm$

6 0

3 years ago