Due to the fact nitrogen diffuses faster than chlorine nitrogen has insures called co2 which implodes the chlorine which leads to nitrogen having a faster diffusion
The cofficent is 2 for diphosphorus trioxide
Answer:
The yield of the product in gram is 
Explanation:
Given that:
the molecular mass weight of the product = 96.2 g/mol
the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g
given that the millimoles of the reagent = 2,7 millimoles = 
We know that:
Number of moles = mass/molar mass
Then:


mass = 0.697
Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100
i.e
Theoretical yield = 
where;
and 
Theoretical yield = 
Given that the theoretical yield = 100%
Then:



where,
= derived weight of the product
the molecular mass of the derived product
the molecular mass of the reagent
= weight in a gram of the reagent



Answer:
Fe₂O₃ and C are reactants
Fe and CO₂ are products
Explanation:
Reactants:
Chemical species that are present on left side of chemical reaction equation are called reactants.
Product:
Chemical species that are present on right side of chemical reaction equation are called product.
Chemical equation:
2Fe₂O₃ + 3C → 4Fe + 3CO₂
In this reaction 2 mole of iron oxide is react with three moles of carbon and produced four moles of iron and three moles of carbon dioxide. There are equal numbers of atoms of all elements present on both side of chemical reaction so this reaction follow the law of conservation of mass.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Answer:
Explanation:
Translated:
Calculate the amount of sugar (C12 H22 O11) in the morning tea if a teaspoon contains 5g of sugar?
Given parameters
Mass of sugar = 5g
Unknown:
Amount of the sugar =?
Solution:
A mole is the amount of substance that contains avogadro's number of particles i.e 6.02 x 10²³
Therefore, to find the number of moles contained in the teaspoon of sugar we use the expression below:
Number of moles = 
Molar mass of C₁₂H₂₂O₁₁ = (12x12) + (1x22) + (16x11) = 342g/mol
Number of moles =
= 0.015mol of sugar
or 0.015 x 6.02 x 10²³, 8.8x10²¹atoms of sugar