Answer:
Explanation:
We must use the Nernst equation
1. Write the equation for the cell reaction
If you want the reduction potential, the pH 5.65 solution is the cathode, and the cell reaction is
<u> E°/V</u>
Anode: H₂(1 bar) ⇌ 2H⁺(1 mol·L⁻¹) + 2e⁻; 0
Cathode: <u>2H⁺(pH 5.65) + 2e⁻ ⇌ H₂(1 bar)</u>; <u> 0 </u>
Overall: 2H⁺ (pH 5.65) ⇌ 2H⁺(1 mol·L⁻¹); 0
Step 2. Calculate E°
(a) Data
E° = 0
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C
n = 2
F = 96 485 C/mol
pH = 5.65
Calculations:
T = 25 + 273.15 = 298.15 K
![\text{H}^{+} = 10^{\text{-pH}} = 2.24 \times 10^{-5}\text{ mol/\L}\\\\Q = \dfrac{\text{[H}^{+}]_{\text{prod}}^{2}}{\text{[H}^{+}]_{\text{react}}^{2}} = \dfrac{(1.00)^{2}}{(2.24 \times 10^{-5})^{2}} =2.00 \times 10^{9}\\\\\\E = 0 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln{2.00 \times 10^{9}}\\\\= -0.01285 \times 21.41 = \textbf{-0.275 V}\\\text{The cell potential for the cell as written is }\boxed{\textbf{-0.275 V}}](https://tex.z-dn.net/?f=%5Ctext%7BH%7D%5E%7B%2B%7D%20%3D%2010%5E%7B%5Ctext%7B-pH%7D%7D%20%3D%202.24%20%5Ctimes%2010%5E%7B-5%7D%5Ctext%7B%20mol%2F%5CL%7D%5C%5C%5C%5CQ%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BH%7D%5E%7B%2B%7D%5D_%7B%5Ctext%7Bprod%7D%7D%5E%7B2%7D%7D%7B%5Ctext%7B%5BH%7D%5E%7B%2B%7D%5D_%7B%5Ctext%7Breact%7D%7D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B%281.00%29%5E%7B2%7D%7D%7B%282.24%20%5Ctimes%2010%5E%7B-5%7D%29%5E%7B2%7D%7D%20%3D2.00%20%5Ctimes%2010%5E%7B9%7D%5C%5C%5C%5C%5C%5CE%20%3D%200%20-%20%5Cleft%20%28%5Cdfrac%7B8.314%20%5Ctimes%20298.15%20%7D%7B2%20%5Ctimes%2096485%7D%5Cright%20%29%20%5Cln%7B2.00%20%5Ctimes%2010%5E%7B9%7D%7D%5C%5C%5C%5C%3D%20-0.01285%20%5Ctimes%2021.41%20%3D%20%5Ctextbf%7B-0.275%20V%7D%5C%5C%5Ctext%7BThe%20cell%20potential%20for%20the%20cell%20as%20written%20is%20%7D%5Cboxed%7B%5Ctextbf%7B-0.275%20V%7D%7D)
Answer:
C-14 => N-14 + β⁻
Explanation:
C-14 over time decays by beta emission to N-14. Before decay, C-14 nucleus contains 6 protons and 8 neutrons. It is accepted that a neutron (n°) is composed of 1 proton (p⁺) and 1 electron (e⁻). Beta emission indicates loss/discharge of a high energy e⁻ from the nucleus of C-14 leaving 7 protons and 7 neutrons. The number of protons defines the element, N-14 as a product of the decay process with the β particle (high energy electron) the other. To check, remember, the ∑mass Reactants = ∑mass Products (superscript numbers) and ∑reactant charges = ∑product charges (subscript numbers
₆C¹⁴ => ₇N¹⁴ + ₋₁e° or, C-14 => N-14 + β
Answer:
Magnetic
Explanation:
Usually if you look the question up on Google or something you can find a Quizlet that has all the answers
I think it is True because when the plates collide then a volcano forms. (Subduction Zone)
