A. 1/9
Explanation:
The gravitational force between two objects is given by
where
G is the gravitational constant
m1 and m2 are the two masses
r is the distance between the two masses
From the formula, we see that the magnitude of the force is inversely proportional to the square of the distance: therefore, if the distance is tripled (increased by a factor 3), the magnitude of the force changes by a factor
The displacement of the car after the given final velocity is 31.59 m.
The given parameters;
The displacement of the car after the given final velocity is obtained by applying the third kinematic equation as shown below;
v² = u² + 2as
Thus, the displacement of the car after the given final velocity is 31.59 m.
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Answer:
The statement which explains how the total time spent in the air is affected as the projectile's angle of launch increases from 25 degrees to 50 degrees is;
C. Increasing the angle from 25° to 50° will increase the total time spent in the air
Explanation:
The equation that can be used to find the total time, T, spent in the air of a projectile is given as follows;
Where;
T = The time of flight of the projectile = The time spent in the air
u = The initial velocity of the projectile
θ = The angle of launch of the projectile
g = The acceleration due to gravity ≈ 9.81 m/s²
Given that sin(50°) > sin(25°), when the angle of launch, θ, is increased from 25 degrees to 50 degrees, we have;
Let T₁ represent the time spent in the air when the angle of launch is 25°, and let T₂ represent the time spent in the air when the angle of launch is 50°, we have;
sin(50°) > sin(25°), therefore, we have;
Therefore;
T₂ > T₁
Therefore, increasing the angle at which the projectile is launched from 25° to 50° will increase the total time spent in the air.