Answer:
a ball hanging from a tall pole
Explanation:
work is force times a distance in the direction of the force. The ball just hanging there has no motion, so is associated with no work. Work was probably done in the hanging process, but none after.
Answer:
Match with A) Single fixed pulley, B) block & tackle, or C) single moveable pulley
changes the direction of effort; input is 1/2 the distance; or system of pulleys
Explanation:
Answer:
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(Hope this is what you're asking for)
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5. The jogger's velocity is a constant 3.55 m/s between t = 4 s and t = 8 s.
6. Given a linear plot of velocity, the acceleration is determined by the slope of the line. Take any two points on the part of the plot after t = 8 s - for instance, we see it passes through (8 s, 3.5 m/s) and (10 s, 4 m/s) - and compute the slope:
(4 m/s - 3.5 m/s)/(10 s - 8 s) = (0.5 m/s)/(2 s) = 0.25 m/s^2
7. This amounts to finding the area between the velocity function and the time axis and between t = 4 s and t = 8 s. During this time, the velocity is 3.5 m/s. The time interval lasts 4 s. So the distance covered is
(3.5 m/s)*(4 s) = 14 m
8. After 4 seconds, Jimmy's speed decreases from 30.0 m/s to 27.2 m/s, so his acceleration (assuming it was constant) was
a = (27.2 m/s - 30.0 m/s)/(4 s) = -0.200 m/s^2
It's unclear what is meant by "rate of acceleration", since the acceleration is itself a rate. But maybe they just mean to ask for the acceleration, or possibly the magnitude?
To solve this problem it is necessary to apply the concepts related to diffraction through a circular opening.
By definition the angular resolution is given by
Where,
D = Diameter of the lens aperture.
Our values are given as,
Therefore replacing,
Therefore the angular separation is 
