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2 years ago

28. A car with an initial velocity of 24.5 m/s east has an

Physics

1 answer:

zlopas [31]2 years ago

4 0

The displacement of the car after the given final velocity is 31.59 m.

The given parameters;

Initial velocity of the car, u = 24.5 m/s east
Final velocity of the car, v = 18.3 m/s east
Acceleration of the car, a = 4.2 m/s²

The displacement of the car after the given final velocity is obtained by applying the third kinematic equation as shown below;

v² = u² + 2as

$s = \frac{v^2 - u^2}{2a} \\\\s = \frac{(18.3)^2 - (24.5)^2}{2(-4.2)} \\\\s = 31.59 \ m$

Thus, the displacement of the car after the given final velocity is 31.59 m.

Learn more here:brainly.com/question/24666225

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We want to construct a solenoid with a resistance of 4.30 Ω and generate a magnetic field of 3.70 × 10−2 T at its center when ap

marshall27 [118]

Answer with Explanation:

We are given that

Resistance of solenoid,R=4.3 ohm

Magnetic field,B= $3.7\times 10^{-2} T$

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$1 cm=10^{-2} m$

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We know that

$R=\frac{\rho l}{A}$

Where $A=\pi r^2$

Using the formula

$4.3=\frac{1.68\times 10^{-8}\times l}{\pi(0.25\times 10^{-3})^2}$

$l=\frac{4.3\times \pi(0.25\times 10^{-3})^2}{1.68\times 10^{-8}}=50.23 m$

Number of turns of wire= $\frac{l}{2\pi r'}$

Number of turns of wire= $\frac{50.26}{2\pi(1\times 10^{-2}}=800$

Hence, the number of turns of the solenoid,N=799

Magnetic field in solenoid,B= $\mu_0 nI$

$3.7\times 10^{-2}=4\pi\times 10^{-7} n\times 4.6$

$n=\frac{3.7\times 10^{-2}}{4\times 3.14\times 10^{-7}\times 4.6}$

$n=6404 turns/m$

$n=\frac{N}{L}$

$L=\frac{N}{n}$

$L=\frac{799}{6404}$

$L=0.125 m=0.125\times 100=12.5 cm$

Length of solenoid=12.5 cm

1m=100 cm

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Answer:

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3 years ago

6. Dentists use a soft, clay-like material to make a filling for a cavity. The filling stays soft under the

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Answer:

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3 years ago

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3 years ago