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elena-14-01-66 [18.8K]
2 years ago
8

What mass is needed for 5000 moles of iron.

Chemistry
1 answer:
nataly862011 [7]2 years ago
4 0
From Periodic table atomic mass of Iron Fe is 56 grams / mole

I mole of iron, Fe needs 56 grams

5000 would then require :    5000 * 56 = 280 000

 =  280 000 grams or 280 kilograms.
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Explanation:

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Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

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where,

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M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

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Explanation:

9.0122 g be Maybe, sorry i don't think so

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