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Orlov [11]
3 years ago
7

CH3CH2CH3 can interact with other like molecules through

Chemistry
2 answers:
Eddi Din [679]3 years ago
7 0

Answer: dispersion forces, dipole-dipole and hydrogen bonds

Explanation:

8_murik_8 [283]3 years ago
6 0

Answer: dispersion forces

Explanation:

Dispersion forces arise due to temporary shifts in the electron cloud of a molecule. This creates a temporary dipole which could attract another molecule of exactly the same kind, inducing a temporary dipole in the other molecule also and so on. Dispersion forces occur in non polar molecules such as alkanes and are the principal intermolecular forces in operation in such compounds. The given compound is an alkane hence dispersion forces are of paramount importance.

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Any element above 92 on the
Fynjy0 [20]
False
explanation

All of the elements with atomic numbers 1 to 92 can be found in nature, have stable or very long half-life isotopes, and are created as common products of the decay of uranium and thorium.
5 0
3 years ago
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A certain object has a volume of 25.0 ml and a mass of 100 g. what is the density of the object
Tpy6a [65]
Density= mass/volume

             = 100/25
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8 0
3 years ago
Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour
Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>
  • Energy (cal) = 6.85×10⁵ cal
  • Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0
2 years ago
At 25 °C, what is the hydroxide ion concentration, [OH−] , in an aqueous solution with a hydrogen ion concentration of [H+]=4.8×
algol [13]

[OH⁻]= 1 x 10⁻¹⁴ : 4.8 x 10⁻⁴ = 2.083 x 10⁻¹¹

3 0
2 years ago
URGENT is... Mg(ClO3)2
stiv31 [10]

That's a ionic compound because it has a metal and polyatomic parts within the chemical formula.

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