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shtirl [24]
3 years ago
6

What resistance must be connected in parallel with a 633-Ω resistor to produce an equivalent resistance of 205 Ω?

Physics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

303 Ω

Explanation:

Given

Represent the resistors with R1, R2 and RT

R1 = 633

RT = 205

Required

Determine R2

Since it's a parallel connection, it can be solved using.

1/Rt = 1/R1 + 1/R2

Substitute values for R1 and RT

1/205 = 1/633 + 1/R2

Collect Like Terms

1/R2 = 1/205 - 1/633

Take LCM

1/R2 = (633 - 205)/(205 * 633)

1/R2 = 428/129765

Take reciprocal of both sides

R2 = 129765/428

R2 = 303 --- approximated

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krok68 [10]

Answer:

9m^3

Explanation:

Given data

volume  v1=  3m^3

volume  v2=  ???

Temperature T1= 20.0°C.

Temperature T2= 60.0°C.

Applying the relation for temperature and volume

V1/T1= V2/T2

substitute

3/20= V2/60

3*60= V2*20

180= 20*V2

180/20= V2

V2= 9m^3

Hence the final volume is 9m^3

6 0
3 years ago
Change 60cmHg to pascal​
xenn [34]

Answer:

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3 0
3 years ago
Cross section of a solid circular rod is subject to a torque of t = 2.7 kn⋅m . if the diameter of the rod is d = 8 cm , what is
polet [3.4K]
Shear Stress= Force along the tangent/ Area
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3 0
3 years ago
Based on its location in the periodic table, what statement best describes the element Ca
Sergeu [11.5K]
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8 0
3 years ago
The last page of a book is numbered 764. The book is 3.0 cm thick, not including its covers. What is the average thickness (in c
Inessa [10]

Answer:

Thickness of each page will be 0.00785 cm

So option (E) will be correct answer

Explanation:

We have given that last page on the book is numbered as 764

So total number of pages in the book =\frac{764}{2}=382pages ( as each page is numbered in both side )

Total thickness of the book = 3 cm

We have to found the thickness of the each page

So thickness of each page will be =\frac{3}{382}=0.00785cm

So option (E) is correct option

7 0
3 years ago
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