Alright, to begin with. The unit of Force is in Newtons. Meaning the first two options are out of the answers. Now in order to find the force. You will need to take the mass and multiply that by the acceleration. Which will give you 26.75 Newtons.
Answer:
The minimum speed when she leave the ground is 6.10 m/s.
Explanation:
Given that,
Horizontal velocity = 1.4 m/s
Height = 1.8 m
We need to calculate the minimum speed must she leave the ground
Using conservation of energy
![K.E+P.E=P.E+K.E](https://tex.z-dn.net/?f=K.E%2BP.E%3DP.E%2BK.E)
![\dfrac{1}{2}mv_{1}^2+0=mgh+\dfrac{1}{2}mv_{2}^2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7Dmv_%7B1%7D%5E2%2B0%3Dmgh%2B%5Cdfrac%7B1%7D%7B2%7Dmv_%7B2%7D%5E2)
![\dfrac{v_{1}^2}{2}=gh+\dfrac{v_{2}^2}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_%7B1%7D%5E2%7D%7B2%7D%3Dgh%2B%5Cdfrac%7Bv_%7B2%7D%5E2%7D%7B2%7D)
Put the value into the formula
![\dfrac{v_{1}^2}{2}=9.8\times1.8+\dfrac{(1.4)^2}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_%7B1%7D%5E2%7D%7B2%7D%3D9.8%5Ctimes1.8%2B%5Cdfrac%7B%281.4%29%5E2%7D%7B2%7D)
![\dfrac{v_{1}^2}{2}=18.62](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_%7B1%7D%5E2%7D%7B2%7D%3D18.62)
![v_{1}=\sqrt{2\times18.62}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Csqrt%7B2%5Ctimes18.62%7D)
![v_{1}=6.10\ m/s](https://tex.z-dn.net/?f=v_%7B1%7D%3D6.10%5C%20m%2Fs)
Hence, The minimum speed when she leave the ground is 6.10 m/s.
Answer:
3.28 cm
Explanation:
To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:
r = ![\frac{mv}{qB}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7BqB%7D)
Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.
The mass and charge of a proton are:
m = 1.67 * 10^-27 kg
q = 1.6 * 10^-19 C
So, we get that the radius r will be:
r =
= 0.0328 m, or 3.28 cm.
Answer : The correct option is, (c) ![3.7\times 10^2J/^oC](https://tex.z-dn.net/?f=3.7%5Ctimes%2010%5E2J%2F%5EoC)
Explanation :
First we have to calculate the energy or heat.
Formula used :
![E=V\times I\times t](https://tex.z-dn.net/?f=E%3DV%5Ctimes%20I%5Ctimes%20t)
where,
E = energy (in joules)
V = voltage (in volt)
I = current (in ampere)
t = time (in seconds)
Now put all the given values in the above formula, we get:
![E=(3.6V)\times (2.6A)\times (350s)](https://tex.z-dn.net/?f=E%3D%283.6V%29%5Ctimes%20%282.6A%29%5Ctimes%20%28350s%29)
![E=3276J](https://tex.z-dn.net/?f=E%3D3276J)
Now we have to calculate the heat capacity of the calorimeter.
Formula used :
![C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BE%7D%7B%5CDelta%20T%7D%3D%5Cfrac%7BE%7D%7BT_%7Bfinal%7D-T_%7Binitial%7D%7D)
where,
C = heat capacity of the calorimeter
= initial temperature = ![20.3^oC](https://tex.z-dn.net/?f=20.3%5EoC)
= final temperature = ![29.1^oC](https://tex.z-dn.net/?f=29.1%5EoC)
Now put all the given values in this formula, we get:
![C=\frac{3276J}{(29.1-20.3)^oC}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B3276J%7D%7B%2829.1-20.3%29%5EoC%7D)
![C=372.27J/^oC=3.7\times 10^2J/^oC](https://tex.z-dn.net/?f=C%3D372.27J%2F%5EoC%3D3.7%5Ctimes%2010%5E2J%2F%5EoC)
Therefore, the heat capacity of the calorimeter is, ![3.7\times 10^2J/^oC](https://tex.z-dn.net/?f=3.7%5Ctimes%2010%5E2J%2F%5EoC)