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melamori03 [73]
3 years ago
7

4. A light string is attatched to a heavy rope, and the whole thing is pulled tight. A wave is sent along the light string. When

it hits the heavy rope, compared to the wave on the string, the wave that propagates along the rope has the same (A) frequency (B) wavelength (C) both frequency and wavelength (D) neither?
Physics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

The correct answer to the question is (A)

When it hits the heavy rope, compared to the wave on the string, the wave that propagates along the rope has the same (A) frequency

Explanation:

The speed of a wave in a string is dependent on the square root of the tension ad inversely proportional  to the square root of the linear density of the string. Generally, the speed of a wave through a spring is dependent on the elastic and inertia properties of the string

v = \sqrt{ \frac{T}{\mu } } =  \sqrt{ \frac{T}{m/L } }

Therefore if the linear density of the heavy rope is four times that of light rope the velocity is halved and since

v = f×λ therefore  v/2 = f×λ/2

Therefore the wavelength is halved, however the frequency remains the same as continuity requires the frequency of the incident pulse vibration to be transmitted to the denser medium for the wave to continue as the wave is due to vibrating particles from a source for example

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\sigma = 5.67 \times 10^{-8} \;\text{W}\cdot \text{m}^{-2} \cdot \text{K}^{-4}.

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\dfrac{P}{A} = \sigma \cdot T^{4} = 5.67 \times 10^{-8} \times 305.372^{4} = 493\; \text{W}\cdot \text{m}^{-2}.

Keep as many significant figures in T as possible. The error will be large when T is raised to the power of four. Also, the real value will be much smaller than 493\; \text{W}\cdot \text{m}^{-2} since the emittance of a human body is much smaller than assumed.

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brainly.com/question/2526815

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