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tester [92]
3 years ago
12

A 10 kg mass rests on a table. What acceleration will be generated when a force of 20 N is applied and encounters a frictional f

orce of 15 N? A) 0.5 m/s2 B) 3.5 m/s2 C) 5 m/s2 D) 35 m/s2
Physics
1 answer:
kolbaska11 [484]3 years ago
3 0
Yeah. I think that its D too
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In places of hot climate it is advised that the outer walls of houses be painted white. Explain.
goblinko [34]

Darker colors absorb heat, While lighter colors don't. If a house is painted black in Arizona, The black color will absorb the heat making the temperature inside the house very hot even with the AC on. If a house in Arizona is painted White, The heat will bounce off the White color, making the temperature inside the house cooler.

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3 years ago
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A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5 m/s.
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The kinetic energy (KE) is 250 J and the gravitational potential energy (GPE) is 392 J
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3 years ago
HURRY PEASE what happens to current when there is a diode on the circuit and why?
kolbaska11 [484]

Answer:

The current can't 'split down the parallel branch, because the diode is reverse biased so is blocking the flow of current. So basically it's acting as an open circuit. Also when the current flows it wouldn't reduce the currents amount flow through the resistor.

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6 0
3 years ago
Monochromatic light is incident on (and perpendicular to) two slits separated by 0.200 mm, which causes an interference pattern
marusya05 [52]

Answer:

I = 0.636*Imax

Explanation:

(a) To find the fraction of the maximum intensity at a distance y from the central maximum you use the following formula:

I=I_{max}cos^2(\frac{\pi d}{\lambda L}y)   (1)

I: intensity of light

Imax: maximum intensity of light

d: separation between slits = 0.200mm = 0.200 *10^-3 m

L: distance from the screen = 613cm = 0.613 m

y: distance to the central peak of the interference pattern

λ: wavelength of light = 656.3 nm = 656.3 *10^-9 m

You replace the values of all variables in the equation (1):

I=I_{max}cos^2(\frac{\pi (0.200*10^{-3}m)}{(656.3*10^{-9}m)(0.613m)}0.600m)\\\\I=I_{max}cos^2(937.06)=0.636I_{max}

Hence, the fraction of the maximum intensity is I = 0.636*Imax

6 0
3 years ago
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