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tester [92]
3 years ago
12

A 10 kg mass rests on a table. What acceleration will be generated when a force of 20 N is applied and encounters a frictional f

orce of 15 N? A) 0.5 m/s2 B) 3.5 m/s2 C) 5 m/s2 D) 35 m/s2
Physics
1 answer:
kolbaska11 [484]3 years ago
3 0
Yeah. I think that its D too
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Three flat layers of transparent material are stacked upon one another. The top layer has index of refraction n1, the middle has
serg [7]

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7 0
3 years ago
In a hydraulic lift, if the pressure exerted on the liquid by one piston is increased by 100 N/m2 , how much additional weight c
shepuryov [24]

Answer:

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

Explanation:

By means of the Pascal's Principle, the hydraulic lift can be modelled by the following two equations:

Hydraulic Lift - Before change

P = \frac{F}{A}

Hydraulic Lift - After change

P + \Delta P = \frac{F + \Delta F}{A}

Where:

P - Hydrostatic pressure, measured in pascals.

\Delta P - Change in hydrostatic pressure, measured in pascals.

A - Cross sectional area of the hydraulic lift, measured in square meters.

F - Hydrostatic force, measured in newtons.

\Delta F - Change in hydrostatic force, measured in newtons.

The additional weight is obtained after some algebraic handling and the replacing of all inputs:

\frac{F}{A} + \Delta P = \frac{F}{A} + \frac{\Delta F}{A}

\Delta P = \frac{\Delta F}{A}

\Delta F = A\cdot \Delta P

Given that \Delta P = 100\,Pa and A = 25\,m^{2}, the additional weight is:

\Delta F = (25\,m^{2})\cdot (100\,Pa)

\Delta F = 2500\,N

The additional mass needed for the additional weight is:

\Delta m = \frac{\Delta F}{g}

Where:

\Delta F - Additional weight, measured in newtons.

\Delta m - Additional mass, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

If \Delta F = 2500\,N and g = 9.807\,\frac{m}{s^{2}}, then:

\Delta m = \frac{2500\,N}{9.807\,\frac{m}{s^{2}} }

\Delta m = 254.92\,kg

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

3 0
3 years ago
A bee flies at a constant rate of 5 m s until it notices a flower. It then comes to rest in 5 seconds. Find the acceleration of
JulsSmile [24]
Vi=5m/s because that was the speed before it started decelerating
Vf=0m/s because it says it comes to rest
t=5s because it says in the question

a=Vf-Vi/t
a=5m/s/5s
a=1m/s^2
3 0
2 years ago
Read 2 more answers
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