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Andrew [12]
3 years ago
14

A car travels 290 m over a time of 5s. What was the speed of the car?

Physics
1 answer:
Elanso [62]3 years ago
7 0

Answer: 58

Explanation:

I did 290/5

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You are exploring a distant planet. When your spaceship is in a circular orbit at a distance of 630 km above the planet's surfac
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Answer:

R = 24.3 m

Explanation:

As we know that the orbital speed is given as

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here we know that

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R = 4.48 \times 10^6 m

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now we have

5500 = \sqrt{\frac{(6.6 \times 10^{-11})M}{4.48 \times 10^6 + 6.30\times 10^5}}

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now acceleration due to gravity of planet is given as

a = \frac{GM}{R^2}

a = \frac{(6.6 \times 10^{-11})(2.34 \times 10^{24})}{(4.48\times 10^6)^2}

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now range of the projectile on the surface of planet is given as

R = \frac{v^2 sin2\theta}{g}

R = \frac{14.6^2 sin(2\times 30.8)}{7.7}

R = 24.3 m

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