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3 years ago

A year ago If an element has 12 protons and 17 neutrons, how many electrons must it have?

Chemistry

2 answers:

Wewaii [24]3 years ago

7 0

If this element does not have any charge, then there would be 12 electrons.

Dafna1 [17]3 years ago

4 0

if given element is neutral, than it has to have same number of protons and electrons. so in this case it is 12 electrons.

Hope it helps :)

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The iodide (I2) content of a commercial mineral water was measured by two methods that produced wildly different results.6 Metho

hammer [34]

Answer:

Results from method B is more reliable than method A.

Explanation:

The two method that are used for the analysis produced different results. The first method that is method A gives higher value of the iodine content than the method B.

When $Mn^{2+}$ was added to water, method A showed an increased in the iodine content and it increases with the increase in the amount of $Mn^{2+}$ .

Where as in the method B, there is no change in the results. Therefore the measurements provided by the method A shows an inference of $Mn^{2+}$ ion.

The measurement of the iodine content is affected by the presence of the ion $Mn^{2+}$ in water.

Since in method B there is no change in measurement, it is independent of the presence $Mn^{2+}$ ion in water.

As higher iodine content is given by method A, so $Mn^{2+}$ ion must be present in original water that must be interfering the measurement. Hence, method B is more reliable.

3 0

3 years ago

5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a

max2010maxim [7]

Answer: The empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.364g$

Mass of $H_2O=0.0596g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, $\frac{12}{44}\times 0.364=0.0993g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, $\frac{2}{18}\times 0.0596=0.0067g$ of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles$ ]

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = $\frac{0.00828}{0.0067}=1.23\approx 1$

For Hydrogen = $\frac{0.0067}{0.0067}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}$

The general formula of an alkane is $C_nH_{(2n+2)}$ , where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

7 0

3 years ago

Did you write these compounds? KBr 2 NH₂OH 2HNO3

Orlov [11]

The missing components of the neutralisation reaction include the following:

KBr
KBr 2NH4OH
KBr 2NH4OH2HNO2

<h3>What is neutralisation reaction?</h3>

Neutralisation reaction is defined as the type of reaction that leads to the formation of salt and water when an acid and a base reacts.

From the reactions given the missing components are replaced as follows:

HBr + KOH --> KBr + H2O

H2SO4 + 2NH4OH --> (NH4)2SO4 + 2H2O

2HNO3 + Mg(OH)2 --> Mg(NO3)2 + 2H2O

Learn more about acids here:

brainly.com/question/26353151

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2 years ago

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Answer:

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3 years ago

Examples of physical and chemical weathering

lorasvet [3.4K]

Mass is always conserved in a physical change. Energy may be released or absorbed when a substance changes from one physical state to another. In a chemical change, a chemical reaction yields a completely new substance. A substance's particles are changed during a chemical reaction.

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3 years ago