Y-4=2/-3(x-6) I believe that’s the answer hope this helped
A rotation 270° counterclockwise about the origin is the same as rotation 90° clockwise about the origin and has a rule:
(x,y)→(y,-x).
Then:
- D(−2,4)→D'(4,2)
- E(4,7)→E'(7,-4)
- F(10,3)→F'(3,-10)
- G(8,0)→G'(0,-8)
Answer: the coordinates of vertices of quadrilateral D′E′F′G′ are D'(4,2), E'(7,-4), F'(3,-10), G'(0,-8).
The fourth number is 51. 48+49+50+51= 198.
THE NUMER IS 48
Answer:
C) 3,-2,-7,-12
Step-by-step explanation:
A sequence is defined recursively using the formula f(n+1)=f(n)-5. Therefore, 3,-2,-7,-12 is the sequence that could be generated using this formula.
Solving a system of equations we can see that:
They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.
<h3>
How to find how much of each candy needs to be used?</h3>
Let's define the variables:
- x = kilograms of the 40% chocolate.
- y = kilograms of the 60% chocolate.
They want to make 100kg, then:
x + y = 100
And the concentration must be of the 56%, then we can write:
x*0.4 + y*0.6 = (100)*0.56 = 56
Then we have a system of equations:
x + y = 100
x*0.4 + y*0.6 = 56
To solve this, we can isolate x on the first equation to get:
x = 100 - y
Now replace that in the other equation:
(100 - y)*0.4 + y*0.6 = 56
40 + y*0.2 = 56
y*0.2 = 16
y = 16/0.2 = 80
This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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