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3 years ago

How are the helium atoms in this model different from real helium atoms

Chemistry

1 answer:

Charra [1.4K]3 years ago

7 0

We need to see a model pal.

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Chemical reaction precipitate for Ba (NO3)2+K2 CO3?

Alinara [238K]

Yes, because the net ionic is equation will yield BaCO3 as a precipitate because it is insoluble in water

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3 years ago

Read 2 more answers

HELP ME ASAP

gtnhenbr [62]

Answer:D

Explanation:

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3 years ago

Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles of O₂ to t

djverab [1.8K]

Answer : The correct option is (c) $\frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}$

Explanation :

The given balanced chemical reaction is,

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

From the balanced chemical reaction, we conclude that

As, 3 moles of $O_2$ react to give 2 mole of $Fe_2O_3$

So, 1 mole of $O_2$ react to give $\frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}$ moles of $Fe_2O_3$

Thus, the conversion factor needed to convert the number of moles of $O_2$ to the number of moles of $Fe_2O_3$ produced is $\frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}$

Hence, the correct option is (c) $\frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}$

7 0

3 years ago

Read 2 more answers

Which of the following is an isotope of hydrogen

Lena [83]

Z=1 is the formula i would have to see the following lol

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3 years ago

A fluid occupying has a mass of 4mg. Calculate its density and specific volume in SI, EE, and BG units.

kondaur [170]

The question is incomplete, complete question is:

A fluid occupying $3.2 m^3$ of volume has a mass of 4 Mg. Calculate its density and specific volume in SI, EE, and BG units.

Explanation:

1) Mass of liquid = m = 4 Mg = 4 × 1,000 kg = 4,000 kg

(1 Mg = 1000 kg)

Volume of the fluid = V = $3.2 m^3$

Density of the fluid = D

$D=\frac{m}{V}=\frac{4,000 kg}{3.2 m^3}=1,250 kg/m^3$

Specific volume is the reciprocal of the density :

$V_{specific}=\frac{1}{Density}$

Specific volume of the fluid = $S_v$

$S_v=\frac{1}{D}=\frac{1}{1,250 kg/m^3}=0.0008 m^3/kg$

Density of the fluid in English Engineering units = D $(lb/ft^3)$

1 kg = 2.20462 lb

1 m = 3.280 ft

$D=\frac[1,250\times 2.20462 lb}{(3.280 ft)^3=78.95 lb/ft^3$

Specific volume of the fluid :

$=\frac{1}{78.95 lb/ft^3}=0.0127 ft^3/lb$

Density of the fluid in British Gravitational System units = D $(slug/ft^3)$

1 kg = 0.06852 slug

1 m = 3.280 ft

$D=\frac[1,250\times 0.0685218 slug}{(3.280 ft)^3=2.43 slug/ft^3$

Specific volume of the fluid :

$=\frac{1}{2.43 slug/ft^3}=0.412 ft^3/slug$

7 0

3 years ago