All categories

4 years ago

Select all that apply. Which of the following astronomers supported the Earth-centered system?

Physics

2 answers:

Vilka [71]4 years ago

8 0

Answer:

Ptolemy and partially Tycho Brahe

Explanation:

Both Ptolemy and Tycho Brahe believed that the earth was the center of the orbit of the sun, the first also of all the other planets and stars, the later believed the sun was in exchange the center of all the other celestial bodies, then Brahe's posture was an intermediary between that of Ptolemy and the heliocentrism(Sun as center of the solar system, where the planets orbit around it) of Copernicus, that proved to be the right observation later with galileo galilei.

Stella [2.4K]4 years ago

6 0

Among the options, the two astronomers who supported the Earth-centered system were Tycho Brahe and Ptolemy.

Both astronomers developed in fact a system where the Sun was located at the center, while the Earth and the other planets were orbiting around the Sun.

You might be interested in

Stereotypes are widely held beliefs that people have certain traits because

Ray Of Light [21]

Answer:

Stereotypes are widely held beliefs that people have certain traits because they belong to a particular group stereotypes are often in accurate and frequently portray the members of less powerful less controlling groups or negatively and members of more powerful more controlling groups.

4 0

4 years ago

A capacitor with an initial potential difference of 100 V isdischarged through a resistor when a switch between them is closed a

jonny [76]

Answer:

(a). The time constant of the circuit is 2.17.

(b). The potential difference across the capacitor at t=17.0 s is 0.0396 V.

Explanation:

Given that,

Initial potential difference = 100 V

Potential difference across the capacitor = 1.00 V

(a). We need to calculate the time constant of the circuit

Using formula of potential difference

$V(t)=V_{0}e^{\dfrac{-t}{RC}}$

Put the value into the formula

$1.00=100e^{\dfrac{-10.0}{RC}}$

$0.01=e^{\dfrac{-10.0}{RC}}$

On taking ln

$ln(0.01)=\dfrac{-10}{RC}$

$RC=\dfrac{-10}{ln(0.01)}$

$RC=2.17$

(b). We need to calculate the potential difference across the capacitor at t=17.0 s

Using formula again

$V(17)=100e^{\dfrac{-17}{2.17}}$

$V{17}=0.0396\ V$

Hence, (a). The time constant of the circuit is 2.17.

(b). The potential difference across the capacitor at t=17.0 s is 0.0396 V.

7 0

3 years ago

Igoryamba

D. Free fall

Explanation:

An object is said to be in free fall when there is only one force acting on the body, which is the force of gravity.

Near the Earth's surface, the force of gravity acting on a body is given by

F = mg

where

m is the mass of the body

g is the acceleration of gravity (its value is $9.8 m/s^2$ )

The direction of this force is downward (towards the Earth's centre).

If we apply Newton's second law on an object in free-fall, we can find its acceleration. In fact, we have:

$a=\frac{F}{m}$

And substituting F,

$a=\frac{mg}{m}=g=9.8 m/s^2$

So, every object in free-fall accelerates at $9.8 m/s^2$ towards the ground.

Learn more about free fall here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers

3 a A motorcyclist starts from rest and reaches

andrew-mc [135]

The acceleration of the body is 2 m/s^2 while the deceleration is - 1.2 m/s^2.

<h3>What is the acceleration?</h3>

Let us recall that the acceleration is the change in the speed of a body with time. We have been told that the body accelerates for 3s and then decelerates to 2s. This implies that the total time that the object spent in motion is 5 s.

Thus;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v - u/t = a

a = 6 - 0/3

= 2 m/s^2

Again;

v - u/t = a

a = 0 - 6/5