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melisa1 [442]
4 years ago
12

2. A gas absorbs 21.39 kJ of energy while expanding against 0.276 atm from a volume of 0.0432 L to 1.876 L. What is the energy c

hange of the gas?
Chemistry
2 answers:
aksik [14]4 years ago
6 0

Answer:

The energy change of the gas is 21338.74 J

Explanation:

Here we have;

Work done, w by the gas = p×dV

Where:

p = pressure of the gas = 0.276 atm = 27965.7 Pa

dV = Change in volume = V₂ - V₁

V₂ = Final volume of the gas = 1.876 L

V₁ = Initial volume of the gas = 0.0432 L

Therefore, dV = 1.876 - 0.0432 = 1.8328 L = 0.0018328 m³

w = 27965.7×0.0018328 = 51.26 J

Therefore, the energy change = Energy absorbed - Work done

Energy absorbed = 21.39 kJ = 21390 J

Hence, the energy change of the gas = 21390 - 51.26 = 21338.74 J.

Delvig [45]4 years ago
5 0

Answer:

\Delta E=21.34kJ

Explanation:

Hello,

In this case, given the first law of thermodynamics in which the absorbed heat by the system and the work done are related including the energy change as shown below:

Q-W=\Delta E

We can compute the work by knowing the final and initial volumes:

W=P\Delta V=0.276atm\times (1.876L-0.0432L)\\\\W=0.506atm*L*\frac{101.325kPa}{1atm}*\frac{1m^3}{1000L}=0.0513kJ

So we compute the energy change:

\Delta E=21.39kJ-0.0513kJ\\\\\Delta E=21.34kJ

Regards.

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Answer:

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Explanation:

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6 0
3 years ago
If a system performs 147 kJ of work while receiving 47 kJ of heat, what is change in its internal energy?
Verdich [7]

Answer:

-100 kJ

Explanation:

We can solve this problem by applying the first law of thermodynamics, which states that:

\Delta U = Q-W

where:

\Delta U is the change in internal energy of a system

Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)

W is the work done by the system (it is positive if done by the system, negative if done on the system)

For the system in this problem we have:

W = +147 kJ is the work done by the system

Q = +47 kJ is the heat absorbed by the system

So , its change in internal energy is:

\Delta U = +47 - (+147) =-100 kJ

6 0
3 years ago
Which of these could create static electricity?
Vinil7 [7]

c well actually I remember being tought this but I cant remember it 100

6 0
3 years ago
Read 2 more answers
Calculate the de broglie wavelength of a subatomic particle that is moving at 351 km/s if its mass is 9.11 à 10â31 kg. λ = hmuh
gregori [183]

The de Broglie wavelength of a subatomic particle is 2.09 nm.

 λ = h m v = h

momentum : wherein 'h' is the Plank's steady. This equation pertaining to the momentum of a particle with its wavelength is de Broglie equation and the wavelength calculated the use of this relation is de Broglie wavelength.

Frequency is the ratio of velocity and wavelength in relation to hurry. In evaluation, wavelength refers back to the ratio of velocity and frequency.

Wavelength is the gap between the crests of waves or a person's fashionable mind-set. An instance of wavelength is the gap between the crest of two waves. An instance of wavelength is while you and some other character share the equal standard attitude and might for that reason speak properly.

calculation is given in the image below

de Broglie wavelength λ = h/mv

                                          = (6.626 * 10^-34)/9.1 * 10^-31 *351 *10^3

                                          = 2.07 *10^-9

                                 Hence, = 2.op nm    

Learn more about de Broglie wavelength here:-brainly.com/question/16595523

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6 0
2 years ago
An aqueous solution is 40.0 % by mass hydrochloric acid, HCl, and has a density of 1.20 g/mL. The mole fraction of hydrochloric
vivado [14]

Answer:

The molar concentration of HCl in the aqueous solution is 0.0131 mol/dm3

Explanation:

To get the molar concentration of a solution we will use the formula:

<em>Molar concentration = mass of HCl/ molar mass of HCl</em>

<em></em>

Mass of HCl in the aqueous solution will be 40% of the total mass of the solution.

We can extract the mass of the solution from its density which is 1.2g/mL

We will further perform our analysis by considering only 1 ml of this aqueous solution.

The mass of the substance present in this solution is 1.2g.

<em>The mass of HCl Present is 40% of 1.2 = 0.48 g.</em>

The molar mass of HCl can be obtained from standard tables or by adding the masses of Hydrogen (1 g) and Chlorine (35.46 g) = 36.46g/mol

Therefore, the molar concentration of HCl in the aqueous solution is 0.48/36.46 = 0.0131 mol/dm3

7 0
3 years ago
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