b. 460.8 m/s
Explanation:
The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is
where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:
c. 18,000 m
Explanation:
The relationship between speed of the wave, distance travelled and time taken is
where
v = 6,000 m/s is the speed of the wave
d = ? is the distance travelled
t = 3 s is the time taken
Re-arranging the formula and substituting the numbers into it, we find:
Answer:
some symptoms can be lack of energy, and dizziness.
Explanation:
Answer:
182 to 3 s.f
Explanation:
Workdone for an adiabatic process is given as
W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)
where γ = ratio of specific heats. For carbon dioxide, γ = 1.28
For an adiabatic process
P₁V₁ʸ = P₂V₂ʸ = K
K = P₁V₁ʸ
We need to calculate the P₁ using ideal gas equation
P₁V₁ = mRT₁
P₁ = (mRT₁/V₁)
m = 2.80 g = 0.0028 kg
R = 188.92 J/kg.K
T₁ = 27°C = 300 K
V₁ = 500 cm³ = 0.0005 m³
P₁ = (0.0028)(188.92)(300)/0.0005
P₁ = 317385.6 Pa
K = P₁V₁¹•²⁸ = (317385.6)(0.0005¹•²⁸) = 18.89
W = K(V₂¹⁻ʸ - V₁¹⁻ʸ)/(1 - γ)
V₁ = 0.0005 m³
V₂ = 2.10 dm³ = 0.002 m³
1 - γ = 1 - 1.28 = - 0.28
W =
18.89 [(0.002)⁻⁰•²⁸ - (0.0005)⁻⁰•²⁸]/(-0.28)
W = -67.47 (5.698 - 8.4)
W = 182.3 = 182 to 3 s.f
Answer:
vf = 14.2176 m/s
Explanation:
Given
m = 4 Kg
viy = 7.00 ĵ m/s
Fx = 11.0 î N
t = 4.5 s
vf = ?
Using the Impulse - Momentum Theorem, we have
F*Δt = m*Δv ⇒ F*Δt = m*(vf - vi)
⇒ vf = (F*Δt + m*vi) / m
⇒ vf = (F*Δt + m*vi) / m
For <em>x-component</em>
⇒ vfx = (Fx*Δt + m*vix) / m = (11 N*4.5 s + 4 Kg*0 m/s) / (4 Kg)
⇒ vfx = 12.375 î m/s
For <em>y-component</em>
⇒ vfy = (Fy*Δt + m*viy) / m = (0 N*4.5 s + 4 Kg*7 m/s) / (4 Kg)
⇒ vfy = 7 ĵ m/s
Finally:
vf = √(vfx² + vfy²)
⇒ vf = √((12.375 m/s)² + (7 m/s)²)
⇒ vf = 14.2176 m/s
