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Lena [83]
3 years ago
9

Both picric acid and tannic acid are used in the treatment of burns, Why?

Chemistry
1 answer:
Sloan [31]3 years ago
4 0
Both acids have the capability to denature proteins in the skin by altering the tertiary of them. 
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Wind power is:
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Answer) All of the above
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What effect does a catalyst have on a system in equilibrium?
irina1246 [14]

A catalyst is when a chemical reaction occurs faster than normal.

The system is unaffected during a catalyst because both forward and reverse reactions are affected, meaning that quilibrium will occur faster nothing will change.


Hope it helped,


BioTeacher101

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Generally, which of the three families of elements (metals, nonmetals, or inert gases) has the least tendency to form ionic bond
Sergio [31]

Answer:

Inert gases

Explanation:

Inert elements have a stable electron configuration meaning their shells/orbitals are full with their requisite number of electrons. Therefore, gaining or losing an electron would take high ionization energy. Therefore they are less likely to be involved in chemical reaction unless a high amount of energy is used. An example of an inert gas is Helium.

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3 years ago
Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr
lions [1.4K]

Charles's Law i think

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3 years ago
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An atom (not a hydrogen atom) absorbs a photon whose associated wavelength is 300 nm and then immediately emits photon whose ass
KIM [24]

Answer:

The net energy is 2.196 eV

Explanation:

Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.

Using:

ΔE = h*c*(1/λ_{1} - 1/λ_{2})

where:

ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602*10^{-19} J.

h = 4.135*10^{-15} eVs

c = 3*10^{8} m/s

λ_{1} = 300 nm = 300*10^{-9} m

λ_{2} = 640 nm = 640*10^{-9} m

Thus:

ΔE = 4.135*10^{-15} eVs*3*10^{8} m/s*(\frac{1}{300*10^{-9}m } }-\frac{1}{640*10^{-9}m })

ΔE = 4.135*10^{-15}*3*10^{8}*1.77*10^{6} eV = 2.196 eV

6 0
3 years ago
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