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Lena [83]
3 years ago
9

Both picric acid and tannic acid are used in the treatment of burns, Why?

Chemistry
1 answer:
Sloan [31]3 years ago
4 0
Both acids have the capability to denature proteins in the skin by altering the tertiary of them. 
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Liquid to gas require heat?
Anton [14]

Answer:

yes

Explanation:

5 0
2 years ago
Read 2 more answers
Balance chemical equation Calcium hydroxide + carbon dioxide = calcium carbonate + water
dmitriy555 [2]

Answer:

yaeh

Explanation:

a)Ca(OH)

2

​

+CO

2

​

⟶CaCO

3

​

+H

2

​

O

No. of atoms:Ca−1;O−4;H−2;C−1

b)Zn+AgNO

3

​

⟶ZnNO

3

​

+Ag

No. of atoms:Zn−1;Ag−1;N−1;O−3.

7 0
3 years ago
H2(g)+p4(s)ph3(g) what the answer ?
disa [49]

Answer:

6H2 + P4→ 4PH3

Explanation:

Phosphorus has 4 in it and hydrogen has 3 in it. in order to balance it, we have to put 4 in front of phosphine so that the phosphorus on the product side has an equal amount as to the one on the reactant side.

the only one left to balance is hydrogen and so in order to balance it we put a 6 on h2 because the hydrogen in the product size becomes 12 (4 * 3).

therefore the hydrogen on the reactant side becomes 12 as well (6 * 2)

8 0
3 years ago
Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z
Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga  →  ⁶⁷Zn  

The reaction is:

^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0
3 years ago
Select the keyword or phrase that will best complete each sentence. must undergo addition because they have easily broken tt bon
STatiana [176]

Alkenes must undergo addition because they have easily broken tt bonds.

Markonikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.

alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.

Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.

In hydroboration, the boron atom bonds to the substituted carbon.

Hydroxides, amines and alcoxides undergo substitution and elimination, but can do so only when the heteroatom is made into a good leaving group.

8 0
3 years ago
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