Answer:
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PH + pOH = 14
pH = 14 - pOH
pH = 14 - 8.7
pH = 5,3
This solution is <u>acidic</u>.
If pH<7 - acidic
If pH=7 - neutral
If pH>7 - basic
Molar mass of Na2SO4*10H2O is 322.1949 g/mol
The answer is 0.975 L
Volume = mol/Molarity
We have molarity (0.788 M) and we need mol and volume. Let's first calculate number of moles of CaCl2 in 85.3 g:
Molar mass of CaCl2 is sum of atomic masses of Ca and Cl:
Mr(CaCl2) = Ar(Ca) + 2Ar(Cl) = 40 + 2 * 35.45 = 40 + 70.9 = 110.9 g/mol
So, if 110.9 g are in 1 mol, 85.3 g will be in x mol:
110.9 g : 1 mole = 85.3 g : x
x = 85.3 g * 1 mole / 110.9
x = 0.769 moles
Now, calculate the volume:
V = 0.769/0.788
V = 0.975 L
