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hjlf
3 years ago
7

For the following word equations, write it as a chemical equation, then balance it.

Chemistry
1 answer:
Lorico [155]3 years ago
7 0

4K+O2-----------2K2O

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Cathode-electrolyte interphase in lithium batteries revealed by cryogenic electron microscopy. matte
Ksju [112]

Cryo-EM is used to preserve and characterize cycled positive electrodes. Under regular cycling conditions, there isn't an intimate coating layer like CEI.A small electrical short can cause a stable conformal CEI to form in place. The conformal CEI's chemistry is revealed by EELS and cryo-(S)TEM.

It has been assumed that the intimate coating layer generated on the positive electrode, known as cathode electrolyte interphase (CEI), is crucial. However, there are still numerous questions about CEI. This results from the absence of useful instruments to evaluate the chemical and structural characteristics of these delicate interphases at the nanoscale. Here, using cryogenic electron microscopy, we establish a methodology to maintain the natural condition and directly see the interface on the positive electrode.

Learn more about Cathode electrolyte interphase here:

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4 0
2 years ago
What does the law of conservation of energy state?
Anarel [89]

Answer:

it states that the total mass of the products are the same as the total mass of the reactants in a chemical reaction.

Explanation:

4 0
3 years ago
The materials in the flux covering on an electrode determine the electrical characteristics of the electrode.
nataly862011 [7]

Answer:

a. true

Explanation:

It is true that, the materials in the flux covering on an electrode determine the electrical characteristics of the electrode.

8 0
2 years ago
Does H₂O have a subscript?
erma4kov [3.2K]
<span> 2 hydrogen atoms attached to an oxygen atom.</span>
7 0
3 years ago
Read 2 more answers
? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







</span>
3 0
3 years ago
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