A series circuit has only one path for current,
while a parallel circuit has more than one.
Velocity = 90 km/h = 25 m/s
Drag coefficient, Cd = 2D/Density of air*Frontal area*sqr. velocity
Substituting,
Cd = (2*230)/(1.164*1.25*1.65*25^2) = 0.3066
Answer:
- The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.
- The voltage across each of the capacitors is the same.
- The sum of the charge stored on each capacitor is equal to the charge supplied by the battery.
Explanation:
The capacitance connected in parallel will have the same potentials across its ends. If the battery has a charge Q, it is divided among the capacitors.
That is,
Q = q₁ + q₂ + q₃
But, the potential is shared equally as V. So, the individual capacitance of the equation has the form q₁ = C₁V , q₂ = C₂V, etc.
So, in this case, when the effective capacitance is formulated, it would be
C = C₁ + C₂ + C₃ farad
Therefore, the true statements are
The equivalent capacitance of the combination is greater than the capacitance of either of the capacitors.
The potential across each of the capacitors is the same.
The charge supplied by the battery divided among the capacitors.
Answer: If the other two frequencies are F and F1 then;
F-364=2
F=364+2
F=366Hz
364-F1=2
F1=364-2
F1=362Hz
Hence the two possible frequencies are 362Hz and 366Hz
Explanation: